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2 years ago

True or false condensation occurs when liquid is converted to a solid

Chemistry

2 answers:

Snowcat [4.5K]2 years ago

5 0

Answer:

If you cool a gaseous substance, you can watch the phase changes that occur. The phase changes are: Condensation — going from a gas to a liquid. Freezing — going from a liquid to a solid.

Do what you please with that answer.

ikadub [295]2 years ago

4 0

Answer:

False.

Explanation:

When a liquid turns into a solid it is called melting, what you are referring is when gas turns into liquid.

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When 1.5 grams of magnesium burns, how many grams of magnesium oxide will be formed?

SashulF [63]

The balanced chemical reaction for this would be written as:

2Mg + O2 = 2MgO

We use this reaction and the amount of the reactant given to calculate for the amount of magnesium oxide that is produced. We do as follows:

1.5 g Mg (1 mol / 24.31 g) ( 2 mol MgO / 2 mol Mg ) (40.30 g /1 mol ) = 2.49 g MgO produced

6 0

2 years ago

An ideal gas is contained in a cylinder with a volume of 5.0x102 mL at a temperature of 30°C and a pressure of 710. Torr. The ga

Scorpion4ik [409]

Answer:

51207 torr is the new pressure of the gas

Explanation:

We can solve this question using combined gas law that states:

P1V1T2 = P2V2T1

Where P is pressure, V volume and T absolute temperature of 1, initial state and 2, final state of the gas

Computing the values of the problem:

P1 = 710torr

V1 = 5.0x10²mL

T1 = 273.15 + 30°C = 303.15K

P2 = ?

V2 = 25mL

T2 = 273.15 + 820°C = 1093.15K

Replacing:

710torr*5.0x10²mL*1093.15K = P2*25mL*303.15K

3.881x10⁸torr*mL*K = P2 * 7.579x10³mL*K

P2 = 51207 torr is the new pressure of the gas

4 0

2 years ago

Find the number of CoCl2 units present in a 0.78 mol sample.

stich3 [128]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

1 mole of $\sf{ COCl_2}$ has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of $\sf{COCl_2}$ will have ~

$\qquad \sf \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}$

$\qquad \sf \dashrightarrow \: \approx4.7 \times 10 {}^{23} \: \: \: molecules$

5 0

2 years ago

Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,

djverab [1.8K]

Answer: The reaction proceeds in the forward direction

Explanation:

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

Relation of $K_p\text{ with }K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta n_g}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $6.5\times 10^4$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $35^oC=[35+273]K=308K$

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43$

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.