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2 years ago

An object with a mass of 1.5 kg accelerates 10.0 m/s2? when an unknown force is applied to it. What is the amount of the force?

Physics

1 answer:

Svetlanka [38]2 years ago

7 0

Answer:

15N

Explanation:

f=ma

1.5kg x 10m/so

f= 15N

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1 year ago

What is quantum physics?

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2 years ago

a particle is moving along a circular path having a radius of 4 in such that its position as a function of time is given by thet

ANTONII [103]

Answer:

Explanation:

Given

radius of circular path $r=4\ in.$

Position is given by

$\theta =\cos 2t---1$

Differentiate 1 to angular velocity we get

$\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega =-2\sin 2t----2$

Differentiate 2 to get angular acceleration

$\frac{\mathrm{d} \omega }{\mathrm{d} t}=-2^2\cos 2t ---3$

Net acceleration is the vector summation of tangential and centripetal force

$a_t=\alpha \times r$

$a_t=-4\cos 2t\times 4=-16\cos 2t$

$a_r=\omega ^2\cdot r$

$a_r=(-2\sin 2t)^2\cdot 4$

$a_r=16\sin^2(2t)$

$a_{net}=\sqrt{a_r^2+a_t^2}$

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3 years ago

Explain how fluids exert pressure

Veseljchak [2.6K]

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2 years ago

A circuit is set up such that it has a current of 8 A. What would be the new current if the resistance was increased by a factor

RUDIKE [14]

Answer:

4 A

Explanation:

The relationship between current, voltage and resistance in a circuit is given by Ohm's law:

$V=RI$

where

V is the voltage

R is the resistance

I is the current

The equation can also be rewritten as

$I=\frac{V}{R}$

from which we see that the current is inversely proportional to the resistance, R.

In this problem, the initial current is I = 8 A. Then the resistance is doubled:

R ' = 2R

So the new current is

$I'=\frac{V}{R'}=\frac{V}{2R}=\frac{1}{2}(\frac{V}{R})=\frac{I}{2}=4 A$

so the current is halved.

7 0

3 years ago