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suter [353]
3 years ago
13

A downed pilot fires a flare from a flare gun. The flare an initial speed of 250 m/s and is fired at an angle of 35° to the grou

nd. Find the maximum height the flare will reach. How long does it take for the flare to reach its maximum altitude ? What will be the final vertical velocity ?
Physics
2 answers:
den301095 [7]3 years ago
7 0

Answer:

to reach the maximum altitude? is 15 sec

Explanation:

bagirrra123 [75]3 years ago
7 0

Answer:

Maximum Altitude: vi = 250 m/s At the maximum height q = 35° vy,f = vy,i − g∆t = 0 g = 9.81 m/s2 vy,i = vi (sin q) = g∆t ∆t =  vi (si g n q)  =  (250 9 m .8 / 1 s) m (s / i s n 2  35°) ∆t = 15 s

Vertical Velocity: Vyf = 439.09

Explanation:

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3 years ago
A 50.0 Watt stereo emits sound waves isotropically at a wavelength of 0.700 meters. This stereo is stationary, but a person in a
photoshop1234 [79]

Answer:

a) f' = 432 Hz

b) I = 8.12*10^-4 W/m^2

Explanation:

a) To calculate the frequency of sound waves that car receives, you take into account the Doppler effect. In this case (observer moves away of the source) you have the following formula:

f'=f(\frac{v-v_o}{v+v_s})    (1)

where

f: frequency of the source = ?

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vo: speed of the observer = 40.0 m/s

vs: speed of the source = 0 m/s (stationary)

You replace the values of all parameters in the equation (1):

To calculate f' you first calculate the frequency of the sound wave, by using the following formula:

v=\lambda f\\\\

v: speed of sound

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f=\frac{v}{\lambda}=\frac{343m/s}{0.700m}=480Hz

Next, you replace the values of all parameters in the equation (1):

f'=(490Hz)(\frac{343m/s-40.0m/s}{343m/s})=432Hz

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I=\frac{P}{4\pi r^2}

P: power of the source = 50.0 W

r: distance to the source = 70.0 m

I=\frac{50.0 W}{4\pi(70.0m)^2}=8.12*10^{-4}\frac{W}{m^2}

hence, the intensity is 8.12*10^⁻4 W/m^2

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