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3 years ago

Volume of water displaced

Chemistry

1 answer:

o-na [289]3 years ago

5 0

Answer:

The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid.

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To fill the valence shell, an electrically neutral, unbonded atom with atomic number 8 must add.

nikdorinn [45]

Answer:

2 electrons

Explanation:

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The percent composition for nitrogen in chromium(III) nitrate is 6%.

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3 years ago

A specific steroid has a λmax of 257 nm and a molar absorptivity ε of 11 , 500 L mol − 1 cm − 1 . What is the concentration of t

joja [24]

Answer:

$7.83\times 10^{-6} M$ is the concentration of the compound in a solution.

Explanation:

Using Beer-Lambert's law :

Formula used :

$A=\epsilon \times C\times l$

Where:

A = absorbance of solution

C = concentration of solution

l = path length

$\epsilon$ = molar absorptivity coefficient

We have:

C = ? , l = 1.00 cm, A = 0.090

$\epsilon = 11,500 L/(mol cm)$

$C=\frac{A}{\epsilon l}=\frac{0.090}{11,500 L/(mol cm)\times 1.00 cm}$

$C=7.83\times 10^{-6} M$

$7.83\times 10^{-6} M$ is the concentration of the compound in a solution.

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3 years ago

For a price ceiling to be a binding constraint on the market, the government must set it a above the equilibrium price. b below

beks73 [17]

Answer:

B. Below the equilibrium price

Explanation:Price ceiling is the legal price,impose by The Government or Regulatory agencies above which a product should not be sold. It is also a price control mechanism through which the Government and other Regulatory agencies check the excesses of producers and the middle men(Whole sellers and retailers). The price ceiling has to be fixed below the equilibrium price for it to be binding, because businesses are interested mainly for profit maximization.

4 0

3 years ago

If 50.0 g of formic acid (hcho2, ka = 1.8 x 10^-4) and 30.0 g of sodium formate (NaCHO2) are dissolved to make 500 ml. of soluti

gizmo_the_mogwai [7]

If 50.0 g of formic acid (HCHO2, ka = 1.8 x 10^-4) and 30.0 g of sodium formate (NaCHO2) are dissolved to make 500 ml. of solution, the ph of this solution is 3.35.

Therefore, option C is the correct option.

Given,

Given mass of sodium formate = 30 g

Given mass of formic acid = 50 g

Volume of sodium formate = 500 ml

Volume of formic acid = 500ml

Molar mass of sodium formate = 68 g

Molar mass of formic acid = 46 g

<h3>To calculate concentration of sodium formate and formic acid</h3>

The ratio of number of moles and the volume of solution is Molar concentration of substance.

Concentration of sodium formate

Cb = 30/(68×500)

= 0.00088m

Concentration of formic acid

Ca = 50/(46×500)

= 0.00217m

Now,

by using Henderson hesselbalch equation,

pH = pKa + log(Cb/Ca)

pKa = -log(1.8 × 10^(-4))

= 3.75

pH = 3.75 + log(0.00088/0.00217)

pH = 3.75 - 0.392

pH = 3.35

Thus, we calculated that the value of pH of solution of formic acid and sodium formate is 3.35.

learn more about pH:

brainly.com/question/13423434

#SPJ4

3 0

2 years ago