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Tema [17]
3 years ago
12

If ice has a density of.92g/cm, what is the volume of 1.8 kilograms of ice?

Physics
1 answer:
steposvetlana [31]3 years ago
5 0
Given:
Density = .92 g / cm³
Volume = 1.8 kg
            = (1.8 * 1000) grams
            = 1800 grams
Now,
Density (d) = \frac{Mass (m)}{volume(v)}

volume (v)= \frac{mass(m)}{density(d)}

volume (v)= \frac{1800}{.92}

volume (v)= 1956.521739

volume (v)= 1956.5~ cm^{3}

So, the volume of 1.8 kg of ice is 1956.5 cm³

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A ball is kicked at an angle of 35° with the ground.a) What should be the initial velocity of the ball so that it hits a target
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Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

\theta=35^{\circ}

a.Let v_0 be the initial velocity of the ball.

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Height,h=1.8 m

v_x=v_0cos\theta=v_0cos35

v_y=v_0sin\theta=v_0sin35

x=v_0cos\theta\times t=v_0cos35\times t

t=\frac{30}{v_0cos35}

h=v_yt-\frac{1}{2}gt^2

Substitute the values

1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2

1.8=30tan35-\frac{6574.6}{v^2_0}

\frac{6574.6}{v^2_0}=21-1.8=19.2

v^2_0=\frac{6574.6}{19.2}

v_0=\sqrt{\frac{6574.6}{19.2}}=18.5 m/s

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

t=\frac{30}{18.5cos35}

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

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Explanation: a

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A sinusoidal wave of angular frequency 1,203 rad/s and amplitude 3.1 mm is sent along a cord with linear density 3.9 g/m and ten
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Answer:

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Explanation:

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