Question

If ice has a density of.92g/cm, what is the volume of 1.8 kilograms of ice?

Answer 1

Given:
Density = .92 g / cm³
Volume = 1.8 kg
            = (1.8 * 1000) grams
            = 1800 grams
Now,
$Density (d) = \frac{Mass (m)}{volume(v)}$

$volume (v)= \frac{mass(m)}{density(d)}$

$volume (v)= \frac{1800}{.92}$

$volume (v)= 1956.521739$

$volume (v)= 1956.5~ cm^{3}$

So, the volume of 1.8 kg of ice is 1956.5 cm³