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Tema [17]
3 years ago
12

If ice has a density of.92g/cm, what is the volume of 1.8 kilograms of ice?

Physics
1 answer:
steposvetlana [31]3 years ago
5 0
Given:
Density = .92 g / cm³
Volume = 1.8 kg
            = (1.8 * 1000) grams
            = 1800 grams
Now,
Density (d) = \frac{Mass (m)}{volume(v)}

volume (v)= \frac{mass(m)}{density(d)}

volume (v)= \frac{1800}{.92}

volume (v)= 1956.521739

volume (v)= 1956.5~ cm^{3}

So, the volume of 1.8 kg of ice is 1956.5 cm³

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Consider light energy that is momentarily absorbed in glass and then re-emitted. Compared to the absorbed light, the frequency o
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The frequency of the re-emitted light is identical to that of the absorbed light.

To find the answer, we need to know more about the frequency of light.

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A wave pulse travels along a string at a speed of 230 cm/s . Note that parts a - d are independent and refer to changes made to
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a) The speed of the wave will increase by a factor \sqrt{2}.

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Explanation:

a)

The speed of a standing wave on a string is given by

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In this part of the problem, the tension in the string is doubled, so that the new tension is

T' = 2T

Substituting into the equation, we find the new speed of the wave in the string:

v'=\sqrt{\frac{T'}{m/L}}=\sqrt{\frac{2T}{m/L}}=\sqrt{2}\sqrt{\frac{T}{m/L}}=\sqrt{2}v

So, the speed will increase by a factor \sqrt{2}.

b)

We can solve also this part by referring to the formula

v=\sqrt{\frac{T}{m/L}}

where

T is the tension

m is the mass

L is the length

In this case, the string mass is quadrupled, so the new mass is:

m' = 4m

Substituting into the equation, we find what happens to the speed of the wave:

v'=\sqrt{\frac{T}{m'/L}}=\sqrt{\frac{T}{4m/L}}=\frac{1}{\sqrt{4}}\sqrt{\frac{T}{m/L}}=\frac{1}{2}v

So, the speed of the wave will halve.

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Again, we can solve this part by referring to the same equation

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Substituting into the equation, we find that the new speed is:

v'=\sqrt{\frac{T}{m/L'}}=\sqrt{\frac{T}{m/(4L)}}=\sqrt{4}\sqrt{\frac{T}{m/L}}=2v

So, the speed of the wave will  double.

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