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Olenka [21]
2 years ago
11

Intensity of an earthquake is gennerally hingher near the

Physics
1 answer:
ki77a [65]2 years ago
6 0

Answer:

near the epicenter.

Explanation:

Earthquake intensity is a ranking based on the observed effects of an earthquake in each particular place. Therefore, each earthquake produces a range of intensity values, ranging from highest in the epicenter area to zero at a distance from the epicenter.

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KE=0.5.m.v2 or PE=m.g.h
LUCKY_DIMON [66]

Answer:

1. 37.8J

2. 18 Billion Joules, 18 Gigajoules

3. 9.81 Billion Joules, 9.81 Gigajoules

Explanation:

Use the formulas provided,

KE=(1/2)mv^2 and PE=mgh, noting that g=9.81

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2 years ago
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The scientist who suggested that energy can be created under certain conditions was
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Einstein hope this helped
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3 years ago
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24. A anvil with a mass of 60 kg falls from a height of 9.5 m. How fast is it going right
shepuryov [24]

So they give us this

V=IR

V= 1.8

I=0.4

R=?

So we insert the thing that we know.

1.8=0.4*R

We need to leave our unknown value alone. So if our value of 0.4 is multiplying the unknown value it passes to the other side dividing.

So we have this.

Lastly we solve.

R=4.5ohms

The formula to find R is V=IR

V/I=R

So the resistance will be the Voltage divided by the Current

6 0
2 years ago
A car travels 70 miles in 80 minutes. Which is its average speed per minute
Alexxx [7]
Average speed=total distance travelled/time
3 0
2 years ago
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how do I solve how much time does it take for a satellite moving 15000 miles per hour travel to travel once around the earth 249
iogann1982 [59]

Answer:

The time taken by the satellite to orbit earth at its surface, t = 1.66 hr

Explanation:

Given data,

The velocity of the satellite, v = 15000 miles/hr

The distance of travel, d = 24901 miles,

It is equal to the circumference of earth,

So the time taken by the satellite to orbit earth at its surface,

                           v = d/t

                            t = d/v

Substituting the given values in the above equation,

                            t = 24901 / 15000

                              = 1.66 hr

Hence, the time taken by the satellite to orbit earth at its surface, t = 1.66 hr

3 0
3 years ago
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