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barxatty [35]
3 years ago
7

the floor of a room is in the shape of a square of side 4.8m. the floor is to be covered with square tiles of perimeter 1.2m. Fi

nd the cost of covering the floor if each tile costs rupees 27​
Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

the room square side is 4.8m

Area of the room is= 4.8=²23.04²m

perimeter of square tiles=4a =1.2

a=1.2/4

or a=o.3m

area of the square tiles =0.3²=0.09m²

numbers of the tiles are rcover floor of the room

23.0.4/0.09=256

each tiles cost Rs 27

the total cost=256*27=6912

the th coalst cover by the th floor is Rs .6912

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what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube
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Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
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nevsk [136]

Step-by-step explanation:

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4. AAS or SAA

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3 years ago
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Like terms: in the case of exponents, the same exponents for different numbers
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The sum of two numbers is 37 and the difference is 9. What are the numbers
solmaris [256]

Answer:

23 and 14

Step-by-step explanation:

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3 years ago
Here is the question !
Delvig [45]

Answer:

Step-by-step explanation:

Co-ordinates of F, G and H are:

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H (-9, 10)

You can find the lengths of sides by using the distance formula:

<em>length</em>(FG) = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}} = \sqrt{(1-(-4))^{2} + (10-5)^{2}} = 5\sqrt{2} units

Similarly,

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3 years ago
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