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barxatty [35]
3 years ago
7

the floor of a room is in the shape of a square of side 4.8m. the floor is to be covered with square tiles of perimeter 1.2m. Fi

nd the cost of covering the floor if each tile costs rupees 27​
Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

the room square side is 4.8m

Area of the room is= 4.8=²23.04²m

perimeter of square tiles=4a =1.2

a=1.2/4

or a=o.3m

area of the square tiles =0.3²=0.09m²

numbers of the tiles are rcover floor of the room

23.0.4/0.09=256

each tiles cost Rs 27

the total cost=256*27=6912

the th coalst cover by the th floor is Rs .6912

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Step-by-step explanation:

see the attached figure with numbers to better understand the problem

step 1

Find the measure of angle 5  

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step 2

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we know that

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step 3  

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we have

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step 4

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we know that

m∠6+m∠7=180° ----> by supplementary angles

we have

m∠7=52°

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m∠6+52°=180°

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m∠3+m∠6=180° ----> by consecutive interior angles

we have

m∠6=128°

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we know that

m∠2=m∠3 ----> by vertical angles

we have

m∠3=52°

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m∠2=52°

step 7

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we know that

m∠1+m∠3=180° ----> by supplementary angles

we have

m∠3=52°

therefore

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step 8

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