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3 years ago

An unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below

Chemistry

2 answers:

gizmo_the_mogwai [7]3 years ago

8 0

Ans: D) 6

A reaction is said to be balanced when the number of atoms (of one type) is the same in both the reactants and the product side of the equation.

The given reaction is:

BF3 + Li2SO3 → B2(SO3)3 + LiF

Reactants Products

B = 1 B = 2

F = 3 F = 1

Li = 2 Li = 1

S = 1 S = 3

O = 3 O = 9

From the above atoms tally, it is clear that the B, F, Li, S and O atoms are unbalanced.

In order to balance it, multiply BF3 by 2, Li2SO3 by 3 and LiF by 6. The balanced equation is:

2BF3 + 3Li2SO3 → B2(SO3)3 +6 LiF

Therefore, coefficient of LiF is 6

Kazeer [188]3 years ago

3 0

The correct answer is 6 Lithium Flouride

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In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to

labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of $NH_3$ = 100 g

Molar mass of $NH_3$ = 27 g/mole

Molar mass of $N_2$ = 28 g/mole

First we have to calculate moles of $NH_3$ .

$\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles$

The given balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given reaction, we conclude that

2 moles of $NH_3$ produced from 1 mole of $N_2$

3.7 moles of $NH_3$ produced from $\frac{1mole}{2mole}\times 3.7mole=1.85moles$ of $N_2$

Now we have to calculate the mass of $N_2$ .

Mass of $N_2$ = Moles of $N_2$ × Molar mass of $N_2$

Mass of $N_2$ = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0

3 years ago

How many moles of water are in a beaker with 50 mL?

tatiyna

Answer:

Number of moles = 2.8 mol

Explanation:

Given data:

Number of moles of water = ?

Volume of water = 50 mL

Density of water = 1.00 g/cm³

Solution:

1 cm³ = 1 mL

Density = mass/ volume

1.00 g/mL = mass/ 50 mL

Mass = 1.00 g/mL× 50 mL

Mass = 50 g

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 50 g / 18 g/mol

Number of moles = 2.8 mol

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3 years ago

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Explanation:

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Answer:

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