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kramer
3 years ago
5

If the efficiency of the boiler is 91.2 % , the overall efficiency of the turbine, which includes the Carnot efficiency and its

mechanical efficiency, is 46.9 % , and the efficiency of the generator is 98.4 %, what is the efficiency of the total generating unit? (Another 5.0 % needs to be subtracted for other plant losses.)
Engineering
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

Net efficiency of generating unit = 42.08 - 5 = 37.08 %

Explanation:

We have given that efficiency of the boiler = 91.2 % = 0.912

Carnot efficiency = 46.9 % = 0.469

Efficiency of generator = 98.4% =0.984

We have to find the efficiency of total generating unit

For finding the efficiency of total generating unit we have to multiply all the efficiencies

So efficiency of generating unit = 0.912×0.469×0.984 = 0.4208 = 42.08 %

For plant losses we have to subtract 5%

So net efficiency of generating unit = 42.08 - 5 = 37.08 %

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Create a project named CarDealer that contains a Form for an automobile dealer. Include options for at least three car models. A
PIT_PIT [208]

Answer:

/****************** The code for a form application that uses radioButtons * *and displays new form based on the user selection *****************/

Using system;

Using system windows forms;

namespace CarDealer

{

Public partial class Form1 : Form

{

public Form1()

{

//default constructor to initialize components

InitializeComponent();

}

//when user clicks on the details button

private void detail_Click

(Object sender, EventArgs e)

{

if (model1,Checked)

{

Forms2 f = new Form2()

f.ShowDialog()

model1.Checked = false

}

if (model2.Checked)

{

Form3 f = new Form3();

f.ShowDialog();

model2.Checked = false;

}

if (model3.Checked)

{

Form4 f = new Form4();

f.ShowDialog();

model3.Checked = false;

}

}

}

}

Explanation:

Program plan

- Design form: Place label controls with text as select car model and one empty label control to display total price. Change front type and size from each other labels properties window.

- Add three radio buttons with text Renault Kwit, Tata Tiago, Mahindra KUV 100.

- Add button with text View Details.

- Add 3 new windows form from project menu for each car model.

- Change form name and respective car models.

- Place picturebox control to each form by using image property add .jpeg image and place label control containing price of each model to each form

- When user select car model and click on view details, new form containing car model details is displayed.

Form Design is attached below

7 0
3 years ago
This question is 100 points<br> I NEED HELP!!!
Mamont248 [21]

Answer:

hey if u repost this i can answer it u and u dont have to waste this much points but its super blury and not even able to read a single word

8 0
3 years ago
Read 2 more answers
An aquifer has three different formations. Formation A has a thickness of 8.0 m and hydraulic conductivity of 25.0 m/d. Formatio
saveliy_v [14]

Answer:

The horizontal conductivity is 41.9 m/d.

The vertical conductivity is 37.2 m/d.

Explanation:

Given that,

Thickness of A = 8.0 m

Conductivity = 25.0 m/d

Thickness of B = 2.0 m

Conductivity = 142 m/d

Thickness of C = 34 m

Conductivity = 40 m/d

We need to calculate the horizontal conductivity

Using formula of horizontal conductivity

K_{H}=\dfrac{H_{A}K_{A}+H_{A}K_{A}+H_{A}K_{A}}{H_{A}+H_{B}+H_{C}}

Put the value into the formula

K_{H}=\dfrac{8.0\times25+2,0\times142+34\times40}{8.0+2.0+34}

K_{H}=41.9\ m/d

We need to calculate the vertical conductivity

Using formula of vertical conductivity

K_{V}=\dfrac{H_{A}+H_{B}+H_{C}}{\dfrac{H_{A}}{K_{A}}+\dfrac{H_{B}}{K_{B}}+\dfrac{H_{C}}{K_{C}}}

Put the value into the formula

K_{V}=\dfrac{8.0+2.0+34}{\dfrac{8.0}{25}+\dfrac{2.0}{142}+\dfrac{34}{40}}

K_{V}=37.2\ m/d

Hence, The horizontal conductivity is 41.9 m/d.

The vertical conductivity is 37.2 m/d.

3 0
3 years ago
What is the best countermeasure against social engineering?
Mkey [24]

Answer:

Hello Monk7294!

Answer:

Employee education

Explanation:

The most important countermeasure for social engineering is employee education. All the employees should be trained to keep confidential data safe. As a part of security education, organizations have to provide timely orientation about their security policy to new employees. The security policy should address the consequences of the breaches.

<em>- I Hope this helps Have an awesome day!</em>

<em>~ Chloe marcus <3</em>

3 0
3 years ago
Determine the pressure difference in N/m2,between two points 800m apart in horizontal pipe-line,150 mm diameter, discharging wat
zlopas [31]

Answer: 10.631\times 10^3\ N/m^2

Explanation:

Given

Discharge is Q=12.5\ L

Diameter of pipe d=150\ mm

Distance between two ends of pipe L=800\ m

friction factor f=0.008

Average velocity is given by

\Rightarrow v_{avg}=\dfrac{12.5\times 10^{-3}}{\frac{\pi }{4}(0.15)^2}\\\\\Rightarrow v_{avg}=\dfrac{15.9134\times 10^{-3}}{2.25\times 10^{-2}}\\\\\Rightarrow v_{avg}=7.07\times 10^{-1}\\\Rightarrow v_{avg}=0.707\ m/s

Pressure difference is given by

\Rightarrow \Delta P=f\ \dfrac{L}{d}\dfrac{\rho v_{avg}^2}{2}\\\\\Rightarrow \Delta P=0.008\times \dfrac{800}{0.15}\times \dfrac{997\times (0.707)^2}{2}\\\\\Rightarrow \Delta P=10,631.45\ N/m^2\\\Rightarrow  \Delta P=10.631\ kPa

8 0
3 years ago
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