Answer:
Option D, only on the portion of the Earth facing directly toward the Moon
Explanation:
Tides are caused by the gravitational pull of moon. The part of earth that faces the moon experiences the highest gravitational force and hence the high tides will occur in this regions only. The regions that do not faces the moon experiences low tides. It is the gravity of moon that attracts the ocean water towards itself.
Hence, Option D is correct
We know, F = m * a
F = 10 * 5
F = 50 N
In short, Your Answer would be 50 Newtons
Hope this helps!
I think A but I dont really know
150 horsepower and 6000 ft-lb of torque.
Let's choose the "east" direction as positive x-direction. The new velocity of the jet is the vector sum of two velocities: the initial velocity of the jet, which is
along the x-direction
in a direction
north of east.
To find the resultant, we must resolve both vectors on the x- and y- axis:




So, the components of the resultant velocity in the two directions are


So the new speed of the aircraft is:
