Answer: weight on Jupiter = 869.75 N
mass on Earth = mass on Jupiter = 35.5 Kg
Explanation:
W = mg
W = weight
m = mass
g = gravitational acceleration [ on the Earth, g₁ = 9,8 N/kg ]
On the Earth,
G₁ = m x g₁ = 347,9 N
On the Jupiter,
G₂ = mg₂
mass on the Earth = mass on the Jupiter !
m = G₁ : g = 347.9 N : 9,8 N/kg = 35.5 kg
G2 : G1 = 2.5
G₂ = 2,5 G₁ = 2,5 x 347.9 N = 869,75 N
Thank you for your question, what you say is true, the gravitational force exerted by the Earth on the Moon has to be equal to the centripetal force.
An interesting application of this principle is that it allows you to determine a relation between the period of an orbit and its size. Let us assume for simplicity the Moon's orbit as circular (it is not, but this is a good approximation for our purposes).
The gravitational acceleration that the Moon experience due to the gravitational attraction from the Earth is given by:
ag=G(MEarth+MMoon)/r2
Where G is the gravitational constant, M stands for mass, and r is the radius of the orbit. The centripetal acceleration is given by:
acentr=(4 pi2 r)/T2
Where T is the period. Since the two accelerations have to be equal, we obtain:
(4 pi2 r) /T2=G(MEarth+MMoon)/r2
Which implies:
r3/T2=G(MEarth+MMoon)/4 pi2=const.
This is the so-called third Kepler law, that states that the cube of the radius of the orbit is proportional to the square of the period.
This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.
The answer is ultraviolet rays
If the car travels
300 km.........................5 hrs
?km ..............................2h
to find out we do (300*2)/5=600/5=120km
also
300km/5h=60km/h
in 2 hours
120km
Answer : B) The cow pulls back on the girl.
From newton’s third law we know that every action has a reaction force pushing back. So when the girl pulls on a cow, the cow is pulling back on her.
