Question

Jamar to the local snack shop near his school He bought 3 hotdogs and 2 bags of chips for $Kenny went to the same snack shop and bought 5 hotdogs and 6 bags of chips for $9.55 ordered 2 hotdogs and 3 bags of chips, then how much did she pay her order?

Answer 1

Answer:

Marcy paid $4.15

Step-by-step explanation:

Given

Represent hotdogs with x and chips with y.

So, we have:

Jamal

$3x + 2y = 4.85$

Kenny

$5x + 6y = 9.55$

See attachment for complete question

Required

Determine the amount for 2x and 3y

From Jamal's and Kenny's orders we have:

$3x + 2y = 4.85$ --- (1)

$5x + 6y = 9.55$ --- (2)

Multiply (1) by 3

$3 * [3x + 2y = 4.85]$

$9x + 6y = 14.55$ --- (3)

Subtract (2) and (3)

$9x - 5x + 6y - 6y = 14.55 - 9.55$

$9x - 5x = 5$

$4x = 5$

Solve for x

$x = \frac{5}{4}$

$x = 1.25$

Substitute $x = 1.25$ in $3x + 2y = 4.85$

$3 * 1.25 + 2y = 4.85$

$3.75 + 2y = 4.85$

Solve for y

$y = \frac{4.85 - 3.75}{2}$

$y = \frac{1.10}{2}$

$y = 0.55$

So, the cost of 2x and 3y is:

$Cost = 2x + 3y$

$Cost = 2*1.25 + 3*0.55$

$Cost = \ 4.15$