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kompoz [17]
3 years ago
12

An object is allowed to fall freely near the surface of an unknown planet. The object falls 72 meters from rest in 4.0 seconds.

The acceleration due to gravity on that planet is
Physics
2 answers:
dimaraw [331]3 years ago
7 0
<span>it fairly is going to attain a speed of 24 m/s in a 2d, yet between t = 0 and t = a million, it fairly is not any longer vacationing at that speed, yet at slower speeds. it fairly is 12 meters. ?D = [ ( a?T^2 + 2?Tv_i ) ] / 2 the place: ?D = displacement a = acceleration ?T = elapsed time v_i = preliminary speed ?D = [ ( 24m/s^2 • 1s • 1s + 2 • 1s • 0m/s ) ] / 2 ?D = 24 / 2 ?D = 12m</span>
Zanzabum3 years ago
4 0

Answer:

Acceleration due to gravity on that planet, a = 9 m/s²

Explanation:

Initial velocity, u =  0 m/s

Acceleration due to gravity , a = ?

Displacement, s = 72 m

Time , t = 4 s

We have equation of motion s= ut + 0.5 at²

Substituting

   s= ut + 0.5 at²

    72 = 0 x 4 + 0.5 x a x 4²

   a = 9 m/s²

Acceleration due to gravity on that planet, a = 9 m/s²

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If the kinetic energy of an electron is 4.1e-18 j, what is the speed of the electron? (you can use the approximate (nonrelativis
arlik [135]
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K= \frac{1}{2}mv^2
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3 0
3 years ago
Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.
andriy [413]

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F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g

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3 years ago
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Viefleur [7K]

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So since h= 4.90

Then the ans is 3x h = 3h

3 0
3 years ago
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