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Vera_Pavlovna [14]
3 years ago
6

The honda insight, a hybrid electric vehicle, has an u.s. environmental protection agency (epa) gas mileage rating of 57 mi/gal

in the city. how many kilometers can the insight travel on the amount of gasoline that would fit in a soda can? the volume of a soda can is 355 ml.
Physics
1 answer:
sergiy2304 [10]3 years ago
3 0
Convert mL to gallons as follows:

355 mL = 0.355 L 
0.355 L * (1 gal/3.785 L) = 0.0938 gallons

The equivalent km covered would be 

57miles/gal * 0.0938 gal * (1.61 km/ 1 mile) = 8.61 kilometers

I hope I was able to help you. Have a good day!
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All the different habitats in our world make up biodiversity

Explanation:

Biodiversity is the sum of different species in life. With different species, it's diverse because it's more than one type.

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The sampling rate of an ADC is 8.1 kHz. What will be an appropriate cut-off frequency (break frequency) for the anti-aliasing fi
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Answer:

4000 Hz

Explanation:

An anti-alias filter is usually added in front of the ADC to limit a certain range of input frequencies in order to avoid aliasing. This filter is usually a low pass filter that passes low frequencies but attenuates the high frequencies.

The Nyquist sampling criteria states that the sampling rate should be at least twice the maximum frequency component of the desired signal.

Sampling rate = 2(max input frequency)

From the relation we can find out the cut-off frequency for the anti-aliasing filter.

max input frequency = sampling rate/2

max input frequency = 8100/2 = 4050 Hz

Therefore, 4000 Hz would be an appropriate cut-off frequency for the anti-aliasing filter.

3 0
3 years ago
Two stretched copper wires both experience the same stress. The first wire has a radius of 3.9×10-3 m and is subject to a stretc
maw [93]

The stretching force acting on the second wire, given the data is 588 N

<h3>Data obtained from the question</h3>
  • Radius of fist wire (r₁) = 3.9×10⁻³ m
  • Force of first wire (F₁) = 450 N
  • Radius of second wire (r₂) = 5.1×10⁻³ m
  • Force of second wire (F₂) =?

<h3>How to determine the force of the second wire</h3>

F₁ / r₁ = F₂ / r₂

450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³

cross multiply

3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³

Divide both side by 3.9×10⁻³

F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³

F₂ = 588 N

Learn more about spring constant:

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