Answer:
Have the power company install insulated sleeves (also known as “eels”) over power lines.
Wearing PPE is the only way to prevent being electrocuted
Explanation:
To prevent electrocution at workplace, employers can ensure that the power company install insulated sleeves (also known as “eels”) over power lines. Additionally, the employees should wear PPEs which are insulators to prevent electrocution.
Answer:
Low ambient temperature
Explanation:
Hope this helps. If it did, please mark as brianliest so other people see it. Thanks! - Kai
Given:
![X_{L} = 50.0 \ohm](https://tex.z-dn.net/?f=X_%7BL%7D%20%3D%2050.0%20%5Cohm)
frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz
![V_rms} = 85.0 V](https://tex.z-dn.net/?f=V_rms%7D%20%3D%2085.0%20V)
Solution:
To calculate max current in inductor,
:
At f = 60.0 Hz
![X_{L} = 2\pi fL](https://tex.z-dn.net/?f=X_%7BL%7D%20%3D%202%5Cpi%20fL)
![50.0 = 2\pi\times 60.0\times L](https://tex.z-dn.net/?f=50.0%20%3D%202%5Cpi%5Ctimes%2060.0%5Ctimes%20L)
L = 0.1326 H
Now, reactance
at f' = 45.0 Hz:
![X'_{L} = 2\pi f'L](https://tex.z-dn.net/?f=X%27_%7BL%7D%20%3D%202%5Cpi%20f%27L)
![X'_{L} = 2\pi\times 45.0\times 0.13263 = 37.5\ohm](https://tex.z-dn.net/?f=X%27_%7BL%7D%20%3D%202%5Cpi%5Ctimes%2045.0%5Ctimes%200.13263%20%3D%2037.5%5Cohm%20)
Now,
is given by:
Therefore, max current in the inductor,
= 2.13 A
Answer:
![P_2-P_1=27209h](https://tex.z-dn.net/?f=P_2-P_1%3D27209h)
Explanation:
For pressure gage we can determine this by saying:
The closed tank with oil and air has a pressure of P₁ and the pressure of oil at a certain height in the U-tube on mercury is p₁gh₁. The pressure of mercury on the air in pressure gauge is p₂gh₂. The pressure of the gage is P₂.
![P_1+p_1gh_1=p_2_gh_2+P_2](https://tex.z-dn.net/?f=P_1%2Bp_1gh_1%3Dp_2_gh_2%2BP_2)
We want to work out P₁-P₂: Heights aren't given so we can solve it in terms of height: assuming h₁=h₂=h
![P_2-P_1=27209h](https://tex.z-dn.net/?f=P_2-P_1%3D27209h)