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Nataliya [291]
3 years ago
10

I am in the second period and belong to the same family as silicon

Chemistry
1 answer:
Rudik [331]3 years ago
5 0

Answer:

carbon

Explanation:

carbon has 6e- hence belong to group 4 and period 2

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How many moles are in 1.2x10^3 grams of ammonia(NH3) ?
miskamm [114]

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = 1.2\times 10^3g

Molar mass of ammonia = 17.031 g/mole

Formula used :

\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}

\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles

Therefore, the number of moles present in ammonia is, 70.459 moles.

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3 years ago
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Which of the following is a combustion reaction?
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4 years ago
Necesito saber esto porfavor, ¿ cuales son las ventajas que representan los espectroscopia en cuanto al estudio de los elementos
igomit [66]

Answer:

Por favor,no ponga exactamente lo que pongo,Trate de parafrasear.

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Responde a esta pregunta?

5 0
3 years ago
What are 3 examples of physical change?
bazaltina [42]

Just breaking stuff so yea that’s it

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3 years ago
A 1.26 m aqueous solution of an ionic compound with the formula mx2 has a boiling point of 101.63 ∘c. part a calculate the van't
12345 [234]

<span>Answer is: Van't Hoff factor (i) for this solution is 1.051 .
Change in boiling point from pure solvent to solution: ΔT =i · Kb · b.
Kb - </span><span>molal boiling point elevation constant</span><span> is 0.512°C/m.
b -  molality, moles of solute per kilogram of solvent.
b = 1.26 m.
ΔT = 101.63°C - 100</span>°C = 1.63°C.

i = 1.63°C ÷ (0.512°C/m · 1.26 m).

i = 1.051.

5 0
3 years ago
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