Car is driven first 2.0 hour at the velocity 40 km/h.
We know,
Distance covered = Velocity * time.
Therefore, distance covered by car in first two hours = 40 * 2.0 = 80 km.
Car is driven second 2.0 hour at the velocity 60 km/h.
Therefore, distance covered by car in first two hours = 60 * 2.0 = 120 km.
Total distnace covered = 80 km + 120 km =200 km.
Total time taken = 2.0 + 2.0 = 4.0 hours.
Average velocity =
Plugging values in above formula, we get
= 50 km/h
Therefore, average velocity is 50 km/h.
Answer:
earth
Explanation:
The formula for the orbital period of the moon is given by
As the time period is inversely proportional to the square root of the acceleration due to gravity of the planet.
As the value of acceleration due to gravity on Jupiter is more than the earth, so the period of moon around the earth is large as compared to the period of the moon around the Jupiter when the distance is same.
Answer:
a) 0 < r < R: E = 0, R < r < 2R: E = KQ/r^2, r > 2R: E = 2KQ/r^2
b) See the picture
Explanation:
We can use Gauss's law to find the electric field in all the regions:
EA = qen/e0 where qen is the enclosed charge
Remember that the electric field everywhere outside a sphere is:
E(r) = q/(4*pi*eo*r^2) = Kq/r^2
a)
- For 0 < r < R: There is not enclosed charge because all of it remains on the outer layer of the conducting sphere, therefore E = 0 EA = 0/e0 = 0 E = 0
- For R < r < 2R: Here the enclosed charge is equal Q E = Q/(4*pi*eo*r^2) = KQ/r^2
- For r > 2R: Here the enclosed charge is equal 2Q E = Q/(4*pi*eo*r^2) + Q/(4*pi*eo*r^2) = 2Q/(4*pi*eo*r^2) = 2KQ/r^2
b) At the beginning there is no electric field this is why you see a line in zero, In R the electric field is maximum and then it starts to decrease exponentially with the distance and finally in 2R the field increase a little due to the second sphere to then continue decreasing exponentially with the distance
Answer:
saddle weighs 250 newtons. The mass of the saddle is ____250/9.8 kg______ kilograms. Use g = 9.8 N/kg for gravity.