People will always have something easy to to there handy work
Answer : The equilibrium concentration of T(g) is 0.5 M
Solution :
Let us assume that the equilibrium reaction be:
The given equilibrium reaction is,

The expression of
will be,
![K_c=\frac{[Z][X]^2}{[R][T]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BZ%5D%5BX%5D%5E2%7D%7B%5BR%5D%5BT%5D%5E2%7D)
where,
= equilibrium constant = 16
[Z] = concentration of Z at equilibrium = 2.0 M
[R] = concentration of R at equilibrium = 2.0 M
[X] = concentration of X at equilibrium = 2.0 M
[T] = concentration of T at equilibrium = ?
Now put all the given values in the above expression, we get:
![16=\frac{(2.0)\times (2.0)^2}{(2.0)\times [T]^2}](https://tex.z-dn.net/?f=16%3D%5Cfrac%7B%282.0%29%5Ctimes%20%282.0%29%5E2%7D%7B%282.0%29%5Ctimes%20%5BT%5D%5E2%7D)
![[T]=0.5M](https://tex.z-dn.net/?f=%5BT%5D%3D0.5M)
Therefore, the equilibrium concentration of T(g) is 0.5 M
B. The atomic number of zirconium is 40.
Answer:it is a
Explanation hope this helps .
I assume here that the engine operates following a Carnot cycle, which achieves the maximum possible efficiency.
Under this assumption, the efficiency of the engine (so, the efficiency of the Carnot cycle) is given by

where

is the cold temperature

is the hot temperature
For the engine in our problem, the cold temperature is 313 K while the hot temperature is 425 K, so the effiency of the engine is