The net force on the object as described is; 58.84N
Two forces acting on the object are;
- The <em>applied force and the frictional force.</em>
In essence; the frictional force can be evaluated as;
- Frictional force; = coefficient × Weight of object.
- Frictional force = 0.21 × 20 × 9.8.
- Frictional force = 41.16N
- The Net force = Applied force - frictional force
Net Force = 58.84 N.
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Answer:
They could be jumping off structures, running or climbing on rocks. They also could be participating in sports like soccer.
Explanation:
sources:
https://www.philippinesbasiceducation.us/2013/06/physical-activity-and-physical.html - about there play schedule
http://sportphil.com/category/articles/ - concil of philippines
Sorry that's all I could find.
45 grams is 0.045 kilograms
K (Q1) (Q2)/d^2 =
k : coulumb constant
Q1 : Charge on object 1
Q2 : Charge on object 2
d : distance between two charged object
Answer:
anything that takes up space.
