Answer:
The gravitational force on the moon is less than on Earth because the strength of gravity is determined by an object's mass. The bigger the object, the bigger the gravitational force. Gravity is pretty much everywhere. We just feel it in different ways depending on our state of motion.
Explanation:
Hope this helped!!
Answer:
![9.3\cdot 10^{37}](https://tex.z-dn.net/?f=9.3%5Ccdot%2010%5E%7B37%7D)
Explanation:
Power is defined as the energy produced (E) per unit of time (t):
![P= \frac{E}{t}](https://tex.z-dn.net/?f=P%3D%20%5Cfrac%7BE%7D%7Bt%7D)
This means that the energy produced in the Sun each second (1 s), given the power
, is
![E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J](https://tex.z-dn.net/?f=E%3DPt%3D%284.0%5Ccdot%2010%5E%7B26%7DW%29%281s%20%29%3D4.0%5Ccdot%2010%5E%7B26%7D%20J)
Each p-p chain reaction produces an amount of energy of
![E_1 = 4.3\cdot 10^{-12} J](https://tex.z-dn.net/?f=E_1%20%3D%204.3%5Ccdot%2010%5E%7B-12%7D%20J)
in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:
![n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BE%7D%7BE_1%7D%3D%5Cfrac%7B4.0%5Ccdot%2010%5E%7B26%7D%20J%7D%7B4.3%5Ccdot%2010%5E%7B-12%7D%20J%7D%3D9.3%5Ccdot%2010%5E%7B37%7D)
Answer:
3. if you increase your mass you also increase the gravitational pull
6. Radiant energy doesn't depend on a medium and sound energy is dependent on a medium.
Explanation:
i hope this helps-
Answer:
temperature on left side is 1.48 times the temperature on right
Explanation:
GIVEN DATA:
![\gamma = 5/3](https://tex.z-dn.net/?f=%5Cgamma%20%3D%205%2F3)
T1 = 525 K
T2 = 275 K
We know that
![P_1 = \frac{nRT_1}{v}](https://tex.z-dn.net/?f=P_1%20%3D%20%5Cfrac%7BnRT_1%7D%7Bv%7D)
![P_2 = \frac{nrT_2}{v}](https://tex.z-dn.net/?f=P_2%20%3D%20%5Cfrac%7BnrT_2%7D%7Bv%7D)
n and v remain same at both side. so we have
![\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1%7D%7BP_2%7D%20%3D%20%5Cfrac%7BT_1%7D%7BT_2%7D%20%3D%20%5Cfrac%7B525%7D%7B275%7D%20%3D%20%5Cfrac%7B21%7D%7B11%7D)
..............1
let final pressure is P and temp ![T_1 {f} and T_2 {f}](https://tex.z-dn.net/?f=T_1%20%7Bf%7D%20and%20T_2%20%7Bf%7D)
![P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}](https://tex.z-dn.net/?f=P_1%5E%7B1-%5Cgamma%7D%20T_1%5E%7B%5Cgamma%7D%20%3D%20P%5E%7B1%20-%20%5Cgamma%7DT_1%20%7Bf%7D%5E%7B%5Cgamma%7D)
..................2
similarly
.............3
divide 2 equation by 3rd equation
![\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B11%7D%5E%7B-2%2F3%7D%20%5Cfrac%7B21%7D%7B11%7D%5E%7B5%2F3%7D%20%3D%20%5B%5Cfrac%7BT_1%20%7Bf%7D%7D%7BT_2%20%7Bf%7D%7D%5D%5E%7B5%2F3%7D)
![T_1 {f} = 1.48 T_2 {f}](https://tex.z-dn.net/?f=T_1%20%7Bf%7D%20%3D%201.48%20T_2%20%7Bf%7D)
thus, temperature on left side is 1.48 times the temperature on right