All categories

3 years ago

List two examples of items that undergo sublimation

Chemistry

1 answer:

umka21 [38]3 years ago

8 0

Answer:

Examples of solids that sublime are dry ice (solid carbon dioxide), iodine, arsenic, and naphthalene (the stuff mothballs are made of).

Explanation:

You might be interested in

Hydrochloric acid is found in swimming pools and in your stomach.How does it function in each situation?

DochEvi [55]

HCL in swimming pools helps kill the bacteria in them from other people while HCL in your stomach helps dissolve the food you eat

6 0

4 years ago

WILL MARK BRAINIEST

lions [1.4K]

Answer:

The correct option is B. The nonpolar substance has a lower boiling point than the polar substance.

Explanation:

Substances with hydrogen bonding, an intermolecular force, will have much higher boiling points than those that have ordinary dipole-dipole intramolecular forces. Non-polar molecules have lower boiling points, because they are held together by the weak van der Waals forces.

Note

However, if size of non polar increases, then its boiling point increases due to increases in van der walls forces with large size.

4 0

3 years ago

Read 2 more answers

A beach ball has a mass of 5 g and a volume of 20 cm3. What is the object's density?

ivann1987 [24]

Mass = 5 g

volume = 20 cm³

density = mass / volume

therefore:

D = m / V

D = 5 / 20

D = 0.25 g/cm³

3 0

4 years ago

Lead metal can be extracted from a mineral called galena, which contains 86.6% lead by mass. a particular ore contains 68.5% gal

rjkz [21]

The volume of sphere can be calculated using the following formula:

$V=\frac{4}{3}\pi r^{3}$

Here, r is radius of the sphere which is 8 cm. Putting the value,

$V=\frac{4}{3}\pi r^{3}=\frac{4}{3}(3.14)(8 cm)^{3}=2143.57 cm^{3}$

This is equal to the volume of lead, density of lead is $11.34 g/cm^{3}$ thus, mass of lead can be calculated as follows:

$m=d\times V=11.34 g/cm^{3}\times 2143.57 cm^{3}=2.43\times 10^{4}g$

Let the mass of ore be 1 g, 68.5% of galena is obtained by mass, thus, mass of galena obtained will be 0.685 g.

Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:

m=0.685×0.866=0.5932 g

Therefore, 0.5932 g of lead is obtained from 1 g of ore, if the efficiency is 100%.

For 92.5% efficiency, mass of lead obtained will be:

$m=\frac{92.5}{100}\times 0.5932=0.5487 g$

Thus, 1 g of lead obtain from $\frac{1}{0.5487}=1.822$ grams of ore.

Thus, $2.43\times 10^{4} g$ of lead obtain from:

$2.43\times 10^{4}\times 1.822=4.42\times 10^{4}g=44.2 kg$

Therefore, mass of ore required to make lead sphere is 44.2 kg.

4 0

3 years ago

Read 2 more answers

Calcium has an atomic number of 20 and 2 valence electrons. Oxygen has an atomic number of 8 and 6 valence electrons. Neon has a

Arlecino [84]

Calcium is in group 2 period 4 of periodic table

Oxygen is in group 16 and period 2

neon is in period 2 and group 16.

Explanation:

Valence electron in calcium =2

valence electron in oxygen= 6

valence electron in neon= 8 valence electron.

Calcium is placed in s block group 2 of period 4.

oxygen is placed in period 2 and group 16

Neon is a p block element, placed in period 2 and group 16.

Calcium is a elecropositive element which can share or donates its electrons to for compound, it has oxidation state of +2 and hence placed in group 2

Oxygen is electronegative as it can accept or share 2 electrons to form a bond. It has oxidation of -2.

Example is CaO.

Neon has its outer shell complete it is an inert element which will not share or donate electrons. it has oxidation state of 0

5 0

3 years ago