That would be BaSO4(s) ( s means solid)
Answer:
The pH of the solution is 4.69
Explanation:
Given that,
Mass of potassium = 2.643 grams
Weight of water = 50.00 mL
Weight of HCl=100.00 ml
Mole = 0.120 M
We know that,
is a basic salt.
Let's write it as KY.
The acid
would become HY.
We need to calculate the moles of KY
Using formula of moles



The reaction is

The number of moles of KY is 20.98 m
initial moles = 20.98
Final moles 
We need to calculate the value of pKa(HY)
Using formula for pKa(HY)



We need to calculate the pH of the solution
Using formula of pH
![pH=pKa+log(\dfrac{[KY]}{[KH]})](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cdfrac%7B%5BKY%5D%7D%7B%5BKH%5D%7D%29)
Put the value into the formula


Hence, The pH of the solution is 4.69
Answer: Option (c) is the kinetic energy.
Explanation:
The kinetic energy present within the particles of a substance is known as thermal energy. Measure of average kinetic energy of particles of a substance is known as temperature.
Whereas heat defined as the transfer of thermal energy from a hot object to a cold object.
Enthalpy is defined as the heat gained or lost by a substance in a chemical reaction.
Thermodynamics is the study of relation between heat and work with chemical or physical changes.
Thus, we can conclude that a measure of kinetic energy of particle motion within a substance is temperature.
Answer:
B) Add appropriate quantities of weak acid and its conjugate base to water.
C) Partially neutralize a weak acid solution by addition of a strong base.
(D) Partially neutralize a weak base solution by addition of a strong acid.
Explanation:
A buffer solution is made by a weak acid and its conjugated base or a weak base and its conjugated acid.
If you add a weak acid to water, you can adjust the pH of the buffer solution by adding a strong base.
If ypu add a weak base to water, you can adjust the pH of the buffer solution by adding a strong acid.
Answer:
1.84 L
Explanation:
Using the equation for reversible work:

Where:
W is the work done (J) = -287 J.
Since the gas did work, therefore W is negative.
P is the pressure in atm = 1.90 atm.
However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K); R = 0.0821 (L*atm)/(mol*K)
Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J
is the initial volume = 0.350 L
is the final volume = ?
Thus:
(-287 J)*0.00987 (L*atm)/J = -1.9 atm*(
- 0.350) L
= [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L