All categories

3 years ago

A 25.00 mL sample of the ammonia solution

Chemistry

1 answer:

musickatia [10]3 years ago

3 0

Answer:

1.634 molL-1

Explanation:

The mol ration between NH3 and HCl is 1 : 1

Using Ca Va / Cb Vb = Na / Nb where a = acid and b = base

Na = 1

Nb = 1

Ca = 0.208 molL-1

Cb = ?

Va = 19.64 mL

Vb = 25.00mL

Solving for Cb

Cb = Ca Va / Vb

Cb = 0.208 * 19.64 / 25.0

Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)

Using the dilution equation;

C1V1 = C2V2

Initial Concentration, C1 = ?

Initial Volume, V1 = 25.00 mL

Final Volume, V2 = 250 mL

Final Concentration, C2 = 0.1634 molL-1

Solving for C1;

C1 = C2 * V2 / V1

C1 = 0.1634 * 250 / 25.00

C1 = 1.634 molL-1

You might be interested in

How is glaas made ? I reallyt don't know

Vlad1618 [11]

Glass is formed when sand or rocks are heated to high temperatures and then cooled rapidly to create glass. i learned that from minecraf,t when u put sand in a furnace lol

4 0

3 years ago

How many moles of \ce{Fe2O3}FeX 2 OX 3 will be produced from 27.0 \text{ g}27.0 g27, point, 0, start text, space, g, end tex

ira [324]

Answer : The number of moles of $Fe_2O_3$ produced will be, 0.241 moles.

Solution : Given,

Mass of Fe = 27.0 g

Molar mass of $Fe$ = 56 g/mole

First we have to calculate the moles of $Fe$ .

$\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}=\frac{27.0g}{56g/mole}=0.482moles$

Now we have to calculate the moles of $Fe_2O_3$

The balanced chemical reaction is,

$4Fe+3O_2\rightarrow 2Fe_2O_3$

From the reaction, we conclude that

As, 4 mole of $Fe$ react to give 2 mole of $Fe_2O_3$

So, 0.482 moles of $Fe$ react to give $\frac{0.482}{4}\times 2=0.241$ moles of $Fe_2O_3$

Thus, the number of moles of $Fe_2O_3$ produced will be, 0.241 moles.

6 0

3 years ago

If 1 kg of fuel is used in the above fusion reaction (2 1H + 3 1H--> 4 2He+1 0N) , the resulting helium has a mass of 0.993 k

enot [183]

Δmc
2

For one reaction:
Mass Defect =Δm
=2(m
H

)−m
He

−m
n

=2(2.015)−3.017−1.009
=0.004 amu
1 amu=931.5 MeV/c
2

Hence,
E=0.004×931.5 MeV=3.724 MeV
E=3.726×1.6×10
−13
J=5.96×10
−13
J

For 1 kg of Deuterium available,
moles=
2g
1000g

=500
N=500N
A

=3.01×10
26

Energy released =
2
N

×5.95×10
−13
J
=8.95×10
13

6 0

3 years ago

Which family contains elements with a full octet of valence electrons?

iren [92.7K]

D. the noble gasses !!!!

5 0

4 years ago

Read 2 more answers

How many grams of Ar are there in 2.25 moles of Ar?

nydimaria [60]

Answer:

89.88 g

Explanation:

Atomic Mass of Ar: 39.948

Mass = moles * AM

Replacing moles = 2.25 and AM = 39.948 you get the mass of Ar:

Mass = 2.25 * 39.948

Mass = 89.88 g

8 0

3 years ago