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Explanation:
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Answer:
2.05 radians/s
Explanation:
This is a simple harmonic motion. The angular frequency of a loaded spring is given by
![\omega = \sqrt{\dfrac{k}{m}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D)
where
is the spring constant and
is the mass on the spring.
Using the known values,
![\omega = \sqrt{\dfrac{8}{1.9}} = 2.05](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cdfrac%7B8%7D%7B1.9%7D%7D%20%3D%202.05)
Answer:
Statement:
The electric current passing through a conductor is directly proportional to the potential difference across its ends provided temperature and other physical conditions remain constant.
Explanation:
Current is directly proportional to voltage loss through a resistor. That is, if the current doubles, then so does the voltage. To make a current flow through a resistance there must be a voltage across that resistance. Ohm's Law shows the relationship between the voltage (V), current (I) and resistance (R).
V∝I or I∝V⇒V=IR.
consider the motion along the X-direction
X = horizontal displacement = 80 m
= initial velocity along the x-direction = v Cos60
t = time of travel
using the equation
X =
t
80 = (v Cos60) (t)
t = 160/v eq-1
consider the motion in vertical direction :
Y = vertical displacement = 20 m
= initial velocity in Y-direction = v Sin60
a = acceleration = - 9.8 m/s²
t = time of travel = 160/v
using the equation
Y =
t + (0.5) a t²
20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²
v = 32.5 m/s