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Jlenok [28]
3 years ago
7

27b. You're in an airplane that flies horizontally with speed 1000 km/h (280 m/s) when an engine falls off. Ignore air resistanc

e and assume it takes 30 s for the engine to hit the ground. What is the horizontal distance that the aircraft engine moves during its fall
Physics
1 answer:
jonny [76]3 years ago
6 0

Answer:

8400m

Explanation:

The engine that falls off would have the same constant horizontal velocity as the airplane's when if falls off if we ignore air resistance. So it would have a horizontal velocity of 280m/s for 30seconds before it hits the ground.

Therefor the horizontal distance the engine travels during its fall is

280 * 30 = 8400m

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3 years ago
Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel
andrew-mc [135]

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

7 0
3 years ago
24) Which of the following equations is correctly balanced? HELP ME ASAP PLEASE
hammer [34]

Answer:

the correct answer is option C

7 0
2 years ago
Read 2 more answers
What is the frequency in hertz of a signal that repeats 80,000 times within one minute? What is its period?
Harman [31]

1333.3 is the frequency in the hertz of a signal that repeats 80,000 times within one minute. 0.00075 is its period.

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively.

The length of time it takes for a particle in a medium to complete one full vibrational cycle is the period of a wave. Being a time, a period is measured in time units like seconds, hours, days, or years. The Earth's orbit around the Sun has a duration of around 365 days, and one cycle of the Earth lasts 365 days.

frequency = cycle /second

frequency = 80000 / 60

frequency = 1333.3 hertz

Period = 1 / frequency

Period = 1 / 1,333.3

Period = 0.00075

To know more about  frequency refer to:  brainly.com/question/14472937

#SPJ4

5 0
2 years ago
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