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Jlenok [28]
3 years ago
7

27b. You're in an airplane that flies horizontally with speed 1000 km/h (280 m/s) when an engine falls off. Ignore air resistanc

e and assume it takes 30 s for the engine to hit the ground. What is the horizontal distance that the aircraft engine moves during its fall
Physics
1 answer:
jonny [76]3 years ago
6 0

Answer:

8400m

Explanation:

The engine that falls off would have the same constant horizontal velocity as the airplane's when if falls off if we ignore air resistance. So it would have a horizontal velocity of 280m/s for 30seconds before it hits the ground.

Therefor the horizontal distance the engine travels during its fall is

280 * 30 = 8400m

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Answer:

Explanation:

This problem is based on conservation of angular momentum.

moment of inertia of larger  disc I₁ = 1/2 m r²  , m is mass and r is radius of disc . I

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moment of inertia of smaller  disc I₂ = 1/2 m r²  , m is mass and r is radius of disc . I

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= 31.25 kgm²

3500 rmp = 3500 / 60 rps

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31.25 x 366.3124 = ( 250 +31.25) ω

ω = 40.7 rad / s .

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KATRIN_1 [288]

Answer:

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