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lapo4ka [179]
3 years ago
8

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!

Physics
1 answer:
Bond [772]3 years ago
4 0

Answer:

The answer is A) byee!!

Explanation:

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A Carnot engine whose high-temperature reservoir is at 464 K has an efficiency of 25.0%. By how much should the temperature of t
nexus9112 [7]

Answer

given,

high temperature reservoir (T_c)= 464 K

efficiency  of reservoir (ε)= 25 %

temperature to decrease = ?

increase in efficiency = 42 %

now, using equation

 \epsilon = 1 - \dfrac{T_C}{T_H}

 0.25 = 1 - \dfrac{T_C}{464}

 T_C= (1 - 0.25) \times 464

 T_C= 0.75 \times 464

      T_C = 348 K

now,

if the efficiency is equal to 42$ = 0.42

 T_C= (1 - 0.42) \times 464

 T_C= 0.58 \times 464

 T_C= 269.12\ K

8 0
3 years ago
Find A and B <br> I need help like asap so pleasee help
zloy xaker [14]

Answer:

I don't understand?

Explanation:

Could you please elaborate?

8 0
3 years ago
Science
sukhopar [10]
214 hops this help.hi and good bye
4 0
3 years ago
A rock on the ground weighs 40N. How much force does the ground exert on the rock?
worty [1.4K]

Answer:

The correct option is;

C. 40 N

Explanation:

Given that the rock is on the ground, we have;

The weight of the rock, F_W = 40 N ↓

From Newton's third law of motion, we have that action and reaction are equal and opposite,

Therefore, given that the weight of the rock exerts a force of 40 N on the ground, and the rock is stable and stationery on the ground, then the ground is reacting to the weight of the rock with an equal force of 40 N, acting in opposite direction to the weight of the block to balance the weight of the rock and create equilibrium such that the net force acting on the rock is zero

∑F = F_W + F_R = 0

Where;

F_R = The reaction of the ground

We have;

F_W + F_R= 40 + F_R  = 0

F_R = 0 - 40 = -40

F_R = -40 N ↓

∴ F_R = 40 N ↑.

5 0
4 years ago
A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio
Reika [66]

Answer:

α = -2.303 \times 10^-^9rad/s^2

b)t = 2619.8 years

c) T(i) =  0.0208536s  

Explanation:

Given that ,

The period of pulsar T = 0.033 s

The period increase at a rate of  \frac{dT}{dt} = 1.26×10⁻⁵s/y

a) Pulsar angular speed is

ω = θ / T = 2π / T

θ = one revolution of pulsar

T = period of pulsar

Pulsar angular acceleration is given by

\alpha = \frac{dw}{dt}

\alpha = -\frac{2\pi }{ T^2}\frac{dT}{dt}

\alpha  = -\frac{2\pi }{0.033^2} \frac{1.26 \times 10^-^5}{60\times60\times24\times365.25}

= -2.303 \times 10^-^9rad/s^2

b) ω₀ = θ / T

0 = 190.4 - 2.303 × 10⁻⁹

t = \frac{190.4 }{2.303  \times10^-^9} \\= 8.27 \times10^1^0s \\= 2619.8y

c) 2018 - 1054

= 964years

The pulsar is originated in a supernova explosion 964 years ago.

then the initial period of pulsar

T_i = T - 964 \times \frac{dT}{dt} = 0.033 - 964  \times 1.26  \times 10^-^5 \\= 0.0208536s

T(i) =  0.0208536s

5 0
3 years ago
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