The limiting reactant is salicylic acid (C₇H₆O₃).
Explanation:
We have the following chemical reaction where salicylic acid (C₇H₆O₃) reacts with acetic anhydride (C₄H₆O₃) to form acetylsalicylic acid (C₉H₈O₄) and acetic acid (C₂H₄O₂):
C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + C₂H₄O₂
We have started with 70.0 g of salicylic acid (C₇H₆O₃) and 80.0 g acetic anhydride (C₄H₆O₃).
First we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of salicylic acid = 70 / 138 = 0.507 moles
number of moles of acetic anhydride = 80 / 102 = 0.784 moles
We see from the chemical reaction that 1 mole of acetic anhydride (C₄H₆O₃) reacts with 1 mole of salicylic acid (C₇H₆O₃) so 0.784 moles of acetic anhydride (C₄H₆O₃) will react with 0.784 mole of salicylic acid (C₇H₆O₃) but we only have 0.507 moles of salicylic acid (C₇H₆O₃). The limiting reactant is salicylic acid (C₇H₆O₃).
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A physical exothermic process
Answer:
smallest to largest:
Electron, Neutron, Atom, Molecule, Nucleus
Explanation:
sorry if it's not right
Answer:
1.56 g of water was involved in the reaction
Explanation:
From the stoichiometric equation
2Na + 2H2O = 2NaOH + H2
NB : Mm Na= 23, Mm H2O = ( 2+16)= 18
2(23) of Na requires 2(18) of water
Hence 1.99g of Na will require 1.99×2×18/2(23) of water = 1.56 g of water
Answer:
The atom is oxidized is Ca.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- The oxidation process is the process in which electrons are lost and produce positively charged ions.
- The reduction process is the process in which electrons is gained and negatively charge ions are produced.
- In the reaction of chlorine with calcium:
<em>Ca + Cl₂ → CaCl₂,</em>
Ca loses 2 electrons and is oxidized to Ca²⁺. (Ca <em>→</em> Ca²⁺ + 2e).
Cl is gains 2 electrons in "Cl₂, oxidation state zero" and is reduced to Cl⁻. (Cl₂ + 2e <em>→</em> 2Cl⁻).
