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3 years ago

The density of an object has the equation d = m/v. if an object has a mass of

Physics

1 answer:

Anit [1.1K]3 years ago

7 0

Answer:

<h3>The answer is 1.92 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{2.5}{1.3} \\ = 1.923...$

We have the final answer as

Hope this helps you

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In an extrasolar planetary system containing a single planet, the parent star is measured to move about its center of mass every

Mademuasel [1]

Answer:

Orbital Time Period is 24 years

Explanation:

This can be explained by the definition of time period.

Time period can be defined as the time taken by an object to complete one cycle, here, time taken to complete one revolution.

Also, we know that an extra solar planet which is also called as an exo planet is that planet which is outside our solar system and orbits any star other than our sun. The system in consideration is extra solar system with a single planet.

Therefore, the time taken by the parent star to move about its mass center is the orbital time period that is 24 years.

4 0

3 years ago

Advantages of wave model

quester [9]

Explanation:

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3 years ago

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.370 mm wide. The diffraction pattern is observed

erica [24]

Answer:

Δx = 6.33 x 10⁻³ m = 6.33 mm

Explanation:

We can use the Young's Double Slit Experiment Formula here:

$\Delta x = \frac{\lambda L}{d}\\\\$

where,

Δx = distance between consecutive dark fringes = width of central bright fringe = ?

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

L = distance between screen and slit = 3.7 m

d = slit width = 0.37 mm = 3.7 x 10⁻⁴ m

Therefore,

$\Delta x = \frac{(6.33\ x\ 10^{-7}\ m)(3.7\ m)}{3.7\ x \ 10^{-4}\ m}$

8 0

3 years ago

An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-

kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle $(m_1)=3\times 10^{-28} kg$

mass of heavier Particle $(m_2)=1.51\times 10^{-27} kg$

speed of lighter particle $(v_1)=0.834 c$

Let speed of heavier particle $=v_2$

and Momentum of the particle is given by

$P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}$

$P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}$

$P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}$

$P_1=8.219\times 10^{-28} kg c$

$P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

as momentum is conserved therefore $P_1=P_2$

$8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

$v_2=0.478 c$

3 0

3 years ago

Which scenarios are examples of physical change?

Oxana [17]

Answer:

For example: Freezing, boiling, are physical

Explanation:

3 0

4 years ago

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