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sp2606 [1]
3 years ago
9

A sheet of glass measures one metre by half metre at 0°C. Calculate its area at 30°C, a for

Physics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

0.50027m^{2}

Explanation:

ΔA=2\alpha A_{0} T

Where ΔA is the change in area

There is a 2 since the coefficient for area = 2 x that for the linear coefficient

A_{0} is the original area

\alpha is the coefficient of thermal expansion

And T is the change in temperature

ΔA=2(0.000009)(0.5)(30-0)=0.00027m^{2}

New area= ΔA+A_{0} = 0.5+0.00027=0.50027m^{2}

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Genrish500 [490]

Answer:

True

Explanation:

Sound is all about vibrations.

The source of a sound vibrates, bumping into nearby air molecules which in turn bump into their neighbor's, and so forth.

4 0
3 years ago
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A person, of weight mg, is standing on a scale in an elevator. What will the
uranmaximum [27]

more than mg

Explanation:

the pressure

7 0
3 years ago
You are pushing a 20 N object for 3 meters. If you have to push
Ludmilka [50]

Answer:

For the first equation, the work done would be 60 J, but if it is done with 30 N, it would have been 90 J.

Explanation:

it's actually pretty easy one you practice it for some time. W ( work done in joules ) = F ( force put onto the object in newtons ) * D ( distance traveled in meters ).

5 0
3 years ago
The pressure exerted by a liquid column of depth 0.5 m on the base of its
Alik [6]

Answer:

1020.4kg/m³

35m³

Explanation:

Given parameters:

Depth  = 0.5m

Pressure exerted  = 5000N/m²

Unknown = density of the liquid  = ?

Solution:

To find the density of this unknown liquid, we use the expression below:

       Pressure of liquid  = density x height x acceleration due to gravity

   5000 = density x 0.5 x 9.8

    Density  = 1020.4kg/m³

B.

Density of water  = 1000kg/m³

Mass of water  = 35000kg  

 Unknown:

Volume of water  = ?

Solution:

 The volume of water can be derived from the expression below:

   Volume  = \frac{mass}{density}  

  Volume  = \frac{35000}{1000}    = 35m³

4 0
3 years ago
A sprinter reaches his maximum speed in 2.6 seconds from rest with constant acceleration. He then maintains that speed and finis
Delvig [45]

Answer: maximum speed vmax = 11.42m/s

Explanation:

Given that the sprinter maintained constant acceleration during the first 2.6 seconds.

a = vmax/ta .......1

The distance covered during the acceleration period is;

da = 0.5a(ta)^2 .....2

Substituting equation 1 to 2

da = 0.5(vmax/ta)(ta)^2 = 0.5vmax(ta) .....3

The distance covered during the period of constant speed vmax is;

dv = vmax (tv) ......4

The total distance travelled is

d = da + dv = 100 (Given)

da + dv = 100 ......5

Substituting equation 3 and 4 into 5

0.5vmax(ta) + vmax(tv) = 100

vmax ( 0.5ta +tv) = 100

vmax = 100/(0.5ta + tv) ....6

But,

t = ta + tv

tv = t - ta .......7

Substituting equation 6 into equation 7

vmax = 100/(0.5ta + t - ta)

vmax = 100/(t-0.5ta)

t = 10.06 s

ta = 2.6 s

Substituting the values;

vmax = 100/(10.06 -0.5(2.6))

vmax = 11.42m/s

Note:

ta = acceleration time

tv = constant velocity vmax time

t = overall time

da , dv and d = acceleration, constant velocity and overall distance covered respectively.

8 0
4 years ago
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