Question

g Determine the magnetic field midway between two long straight wires 2.0 cm apart in terms of the current I in one when the other carries 25 A. Assume these currents are in the same direction.

Answer 1

Answer:

$B_{net}$ =$(2\times 10^{-5}T/A).(I-25A)$

Explanation:

Given :

the distance between the two wires is  = 2 cm

                                                                  = 0.02 m

Current in one of the wire, I = 25 A

Now we know that, when the direction of the current is same that is in one direction , the magnetic field at the mid point in between the two wires will oppose each other.

Therefore we know that

$B_{net}$ = $\frac{\mu _{o}\times I_{1}}{2\pi r_{1}}-\frac{\mu _{o}\times I_{2}}{2\pi r_{2}}$

                            =$\frac{(4\pi \times 10^{-7}T.m/A)}{2\pi (1\times 10^{-2}m)}\times (I-25A)$

                            = $(2\times 10^{-5}T/A).(I-25A)$