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Pani-rosa [81]
3 years ago
10

g Determine the magnetic field midway between two long straight wires 2.0 cm apart in terms of the current I in one when the oth

er carries 25 A. Assume these currents are in the same direction.
Physics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

B_{net} =(2\times 10^{-5}T/A).(I-25A)

Explanation:

Given :

the distance between the two wires is  = 2 cm

                                                                  = 0.02 m

Current in one of the wire, I = 25 A

Now we know that, when the direction of the current is same that is in one direction , the magnetic field at the mid point in between the two wires will oppose each other.

Therefore we know that

B_{net} = \frac{\mu _{o}\times I_{1}}{2\pi r_{1}}-\frac{\mu _{o}\times I_{2}}{2\pi r_{2}}

                            =\frac{(4\pi \times 10^{-7}T.m/A)}{2\pi (1\times 10^{-2}m)}\times (I-25A)

                            = (2\times 10^{-5}T/A).(I-25A)

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Can anyone check if my answer is correct ?
ohaa [14]

I believe your answer is correct, because 8.7*10^-7 is equal to 0.00000085347.

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An ice chest at a beach party contains 12 cans of soda at 4.05 °C. Each can of soda has a mass of 0.35 kg and a specific heat ca
BARSIC [14]
Below is the solution:

Heat soda=heat melon 
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<span>15960(t-5)=27300(27-t) </span>
<span>15960t-136500=737100-27300t </span>
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<span>t=873600/43260 </span>
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4 0
3 years ago
Why do you see objects when you shine a flashlight in a dark room?​
Afina-wow [57]

Answer:

We see objects in a dark room due to the emission of light photons which are sensitive to our eyes. Darkness is simply a terminology used to describe the absence of light. Visible light to human is a component of the electromagnetic spectrum. Our eyes have receptors that picks the photons which light releases

Explanation:

3 0
2 years ago
Read 2 more answers
What is the equivalent resistance if you connect three 10.0 Ω resistors in series?
Sonja [21]

Req = 30.0Ω.

When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.

Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω

4 0
3 years ago
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Please answer the number 5 6 and 7. I don't know what to do its our hw in physics. (new lesson as well)
Aleks04 [339]

From the picture, I see that you had no trouble at all with #4.
Well, #5, 6, and 7 are easily handled in exactly the same way.

Just as you did with #4, please sketch these on paper
as I walk you through the solutions.  That'll help you see
immediately what's going on.

#5.b).
Traveling east at 3 m/s for 4 seconds,
he covers  (3 m/s) x (4 sec) = 12 meters.

Traveling south at 5 m/s for 2 seconds,
he covers (5 m/s) x (2 sec) = 10 meters.

The total distance he covers is  (12m + 10m) = 22 meters.

#5.c).
Average speed (scalar)

                           = (distance covered)/(time to cover the distance)

                           = (22 meters)/(6 sec) = 3-2/3 m/s .

#5.d).
Displacement (vector)

                       = distance between the start-point and the end-point,
                          regardless of the route traveled,
                      
  in the direction from the start-point to the end-point.

Distance from the start-point to the end-point =

               √(12² + 10²) = √(144 + 100) = √(244) = 15.62 meters

in the direction of  arctan(10/12) south of east

                             =  39.8° south of east.
 
#5.e).
Average velocity (vector) =

             (displacement vector) / (time)

         =  15.62 meters directed 39.8° south of east / 6 seconds

         =  2.603 m/s directed 39.8° south of east.

 #6).
Magnitude = √(5.2² + 2.1²) = √(27.04 + 4.41) = √31.45 = 5.608 km.

Direction = arctan(5.2/2.1) south of east

                =   68° south of east  =  158° bearing . 

#7).
Magnitude = √(39² + 57²) = √(1521 + 3249) = √( 4770)

                                                                         =  69.07 m/s .

Direction = arctan (57/39) south of west

               =   55.6° south of west

                    Bearing = 214.4°

                    Compass: 0.65° past "southwest by south".  


I'm grateful for the privilege and opportunity to practice my math,
and I shall cherish the bounty of 5 points that came with it.

8 0
3 years ago
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