Question

Aluminum has a density of 2.7 g/cm3. If a chunk of aluminum with a mass of 10.8 g is placed in a graduated cylinder partially filled with water, how much will the water level rise?

Answer 1

 The  water  level that will   rise  is  4  cm^3

calculation

if the density  i s   2.7 g/cm^3  this implies that   

 1cm^3  =  2.7 g
    ?        = 10.8  g

by  cross  multiplication

 (1 cm^3   x 10. 8 g) /2.7  g   =  4  CM^3

Answer 2

Answer:

$4 cm^{3}$

Explanation:

As you can see density of aluminium is 2.7 g/cm3 so in order to calculate the volume of a piece of aluminium that is 10.8 g we just ahve to clear the volume from the density formula:

$Density=\frac{mass}{volume} \\Volume=\frac{mass}{density}$

Now that we have cleared the formula we just have to insert the values:

$Volume=\frac{mass}{density}\\Volume= \frac{10.8}{2.7}\\ Volume= 4 cm^{3}$

So the volume of the aluminum piece is 4 cm3 so the volume of water displaced would be the same, 4 cm3.