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Harlamova29_29 [7]
3 years ago
8

Bruh how did i get 3 warnings and 3 brainliests removed

Physics
2 answers:
Lapatulllka [165]3 years ago
6 0

Answer:

Maybe comments or innapropriate question.

Explanation:

Brums [2.3K]3 years ago
5 0

Answer:

Wait, that can happen? I'm sorry.

Explanation:

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A gas that exists in outer space is made of
vlabodo [156]
Do you mean on a planet?
7 0
3 years ago
Read 2 more answers
Please help! Will give brainly, 50 points!! I don't understand! I just need this to give me a boost on my other questions.
harina [27]

Answer:

The answer to your question is: c = 353 mi/h; Ф = 7.3°

Explanation:

You can see the picture below

To solve this problem, just imagine a right rectangle which the legs is 350 mi/h and 45 mi/h and we are going to find the hypotenuse.

                    c² = a² + b²

                    c² = 350² + 45²

                   c² = 122500 + 2025

                   c² = 124525

                   c = 352.9 ≈ 353 mi/h

tanФ = 45/ 350

tan Ф = 0.12

Ф = 7.3°

8 0
4 years ago
Question 17 of 25
Scorpion4ik [409]

Answer:

The speed of the wave as it travelled through the brass bell is;

B. 4,700 m/s

Explanation:

The given parameters are;

The wavelength of the sound wave produced from the brass bell, \lambda _{(air)}  = 3.5 m

The wavelength of the wave in the brass bell, \lambda _{(brass \ bell)}  = 47 m

The frequency of the wave in the brass bell, f = 100 Hz

The given equation for wave speed, v = f × λ

Therefore, the speed of the wave as it travelled through the brass bell, v _{(brass \ bell)}, is given as follows;

v _{(brass \ bell)} = f × \lambda _{(brass \ bell)} = 100 Hz × 47 m = 4,700 m/s  

The speed of the wave as it travelled through the brass bell =  v _{(brass \ bell)} = 4,700 m/s

5 0
3 years ago
Read 2 more answers
A model airplane is flying horizontally due north at 44 ​mi/hr when it encounters a horizontal crosswind blowing east at 44 ​mi/
Alik [6]

Explanation:

Let i, j and k represents east, north and upward direction respectively.

Velocity due north, v_a=44j\ mi/hr

Velocity of the crosswind, v_w=44i\ mi/hr

Velocity of downdraft, v_d=-22k\ mi/hr (downward direction)

(a) Let v is the position vector that represents the velocity of the plane relative to the ground. It is given by :

v=44i+44j-22k

(b) The speed of the plane relative to the ground can be calculated as :

v=\sqrt{44^2+44^2+22^2}

v = 66 m/s

Hence, this is the required solution.

7 0
3 years ago
A (light) pallet has a load of cases of tomato paste each of which is a cube of length L and has identical mass. Find the center
Dafna1 [17]

Answer:

From left = 1.2L

From back = 0.9L

Explanation:

5 x = 3(L-X) + 2(2L-X)

X = 0.7L

Distance from left = 1.2L

7y = 2(L-X)+1(2L-x)

Y = 0.4L

Distance from back = 0.9L

6 0
3 years ago
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