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Answer:
The mass flow rate of air through the compressor is = 1.044 ![\frac{kg}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bs%7D)
Explanation:
Mass flow rate refrigerant
= 0.1 ![\frac{kg}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bs%7D)
= - 0 °c = 273 K
= 50 °c = 323 K
= 3 KW
= 20 °c = 293 K
= 30 °c = 303 K
From the continuity equation
![m_{1} h_{1} + W_{in} + m_{a} h_{3} = m_{2} h_{2} + m_{a} h_{4}](https://tex.z-dn.net/?f=m_%7B1%7D%20h_%7B1%7D%20%20%2B%20W_%7Bin%7D%20%2B%20m_%7Ba%7D%20h_%7B3%7D%20%20%20%3D%20m_%7B2%7D%20h_%7B2%7D%20%2B%20m_%7Ba%7D%20h_%7B4%7D)
= 0.1 ![\frac{kg}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bs%7D)
![m_{1} h_{1} - m_{2} h_{2} + W_{in} = m_{a} h_{4} - m_{a} h_{3}](https://tex.z-dn.net/?f=m_%7B1%7D%20h_%7B1%7D%20-%20m_%7B2%7D%20h_%7B2%7D%20%20%2B%20W_%7Bin%7D%20%20%20%20%20%3D%20%20m_%7Ba%7D%20h_%7B4%7D%20-%20m_%7Ba%7D%20h_%7B3%7D)
![m C_{p} (T_{1} - T_{2} ) + W_{in} = m_{a} C_{a} (T_{4} - T_{3})](https://tex.z-dn.net/?f=m%20C_%7Bp%7D%20%28T_%7B1%7D%20-%20T_%7B2%7D%20%20%29%20%2B%20W_%7Bin%7D%20%3D%20m_%7Ba%7D%20C_%7Ba%7D%20%20%28T_%7B4%7D%20-%20T_%7B3%7D%29)
Put all the values in above formula
0.1 × 1.5 × ( 273 - 323 ) + 3 =
× 1.005 × ( 303 - 293 )
10.5 =
× 10.05
= 1.044 ![\frac{kg}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bs%7D)
Therefore the mass flow rate of air through the compressor is = 1.044 ![\frac{kg}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bs%7D)
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