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Fofino [41]
3 years ago
5

When the heat of reaction (H=ve), the reaction is Endothermic reaction True False

Chemistry
2 answers:
juin [17]3 years ago
6 0
False because that doesn’t make sense
katrin [286]3 years ago
6 0
The answer is false
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Calculate 4 Srxn for this equation. Round to the
masya89 [10]

Answer:

On edge nuity, it is 79.

Explanation:

Please read the explanation.

Since u have no coefficients, this problem is super easy.

You just add your products, 115.5+69.91 = 185.41

Then add your reactants: 49.8+56.5= 106.3

Then subtract your reactants from your product and round to the nearest whole number.

106.3-185.41=79

It's really easy. Once u understand it, you can do any problem like this. If there is coefficients, just multiply the coefficient by the amount given to you in the problem.

7 0
3 years ago
What is a limited resource in the use of nuclear fission for energy?
lys-0071 [83]
Uranium is the answer
5 0
3 years ago
Match the following metric terms. 1. the basic measure of mass in the metric system meter 2. prefix meaning one-hundredth (.01)
lidiya [134]

Answer: Here's the answer hope this helps

Explanation:

8 0
3 years ago
How many chlorine atoms are there in 12.2 g of ccl4? How many chlorine atoms are there in 12.2 of ? 4.77×1022 atoms?
mash [69]

Answer:- 1.91*10^2^3Cl atoms.

Solution:- We have been given the grams of carbon tetrachloride and asked to calculate the number of atoms of chlorine. It is a three step conversion problem. In the first we convert the grams of carbon tetrachloride to moles of it. In second step we convert moles of carbon tetrachloride to moles of chlorine and in the third step we convert the moles of chlorine to atoms of chlorine.

For grams to mole conversion we need the molar mass of the compound. Molar mass of carbon tetrachloride is 153.82 grams per mol. If we look at the formula of carbon tetrachloride then four chlorine are present in it. It means 1 mol of carbon tetrachloride has four moles of chlorine. The calculations are as follows:

12.2gCCl_4(\frac{1molCCl_4}{153.82gCCl_4})(\frac{4molCl}{1molCCl_4})(\frac{6.02*10^2^3Clatoms}{1molCl})

= 1.91*10^2^3Cl atoms

So, there are 1.91*10^2^3Cl atoms in 12.2 grams of CCl_4 .

6 0
3 years ago
Read 2 more answers
Help me with this please!!! Smart ones help me 18 points
Helen [10]
Hey! The answer would be 1/2.
4 0
3 years ago
Read 2 more answers
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