Answer:
2-Butanone
Explanation:
From the given information:
The presence of mercury as an acid catalyst brings about the addition of water to the triple bond which yields enol. Then, according to Markownikov's rule and after tautomerism has occurred, we have a methyl ketone ( 2- Butanone) as the product.
The answer regarding the transformation is addition and hydration.
Answer:
1. Hydrogen Iodide
2. 6 molecules of Hydrogen Iodide
3. Iodine is the limiting reagent
Explanation:
The image of the illustration in the question has been attached:
1. The illustration represents a mixture of hydrogen ( light blue ) and iodine ( purple )
H₂ + I₂ ---> 2HI
This forms hydrogen iodide.
2. In the given illustration, 6 product molecules of Hydrogen Iodide. This is indicated in the box on the right side of the illustration.
3. The limiting reagent is the reactant that determines how much of the products are made. It is the substance that is totally consumed when the chemical reaction is completed. In the box on the right side of the illustration, you will see that hydrogen which is indicated by blue is in excess. The limiting reagent is the one that is completely consumed which is the iodine.
