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madreJ [45]
3 years ago
8

The illustration to the left represents a mixture of hydrogen ( light blue ) and iodine ( purple ) reacting to form a product. I

n the illustration: The product that forms is . The number of product molecules formed is . The limiting reagent is

Chemistry
1 answer:
Ksju [112]3 years ago
8 0

Answer:

1. Hydrogen Iodide

2. 6 molecules of Hydrogen Iodide

3. Iodine is the limiting reagent

Explanation:

The image of the illustration in the question has been attached:

1. The illustration represents a mixture of hydrogen ( light blue ) and iodine ( purple )

H₂ + I₂ ---> 2HI

This forms hydrogen iodide.

2. In the given illustration, 6 product molecules of Hydrogen Iodide. This is indicated in the box on the right side of the illustration.

3.  The limiting reagent is the reactant that determines how much of the products are made. It is the substance that is totally consumed when the chemical reaction is completed. In the box on the right side of the illustration, you will see that hydrogen which is indicated by blue is in excess. The limiting reagent is the one that is completely consumed which is the iodine.

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The atomic masses of any two elements contain the same number of
den301095 [7]

Answer:

They contain of atoms

Explanation:

That's because atomic weights or masses of each atom of each element are proportional to each other, the same number of atoms of each element will give masses that are also proportional to each other. If you start with 20 oxygen atoms, you will need 40 hydrogen atoms to make the water and you will get 20 molecules of water.

8 0
3 years ago
Gsfdfsveg dgdtdgrgsjrjrjrhrhrjeurjruehrururhrhrhhrhdj okay so I googled this and got nothing ugh help meh
PolarNik [594]

Answer:

1.Magnetosphere

2.Liquid Outer core

3.Atmosphere

4.Lightening

5.Biosphere

6.Blue

7.Dolphins

8.Hydrosphere

9.Ice Caps

10.Lithosphere

11.Latitude

12.Longitude

Explanation:

The invisible field that protect us from solar radiation is called Magnetosphere.

This protective field is created by movement between solid inner core and earth's Liquid outer core.

The layer of gases is called atmosphere.

In addition to wind , rain , lightening is observed on stormy night.

Because of water earth looks Blue.

Dolphins are just one of the animals that calls the hydrosphere, its home.

Ice caps in the north and south poles.

Rocky layer of solid earth is part of Lithosphere.

Look for the latitude first ,horizontal line ...

8 0
3 years ago
What is the mass of sodium in 3 moles of sodium chloride
SashulF [63]

4.00 moles of sodium has a mass of 91.96 grams.

To find an element's molar mass, you can use its atomic weight.

8 0
4 years ago
When an ionic compound dissolves in water, the individual ions first leave the crystal lattice and then each ion becomes surroun
vichka [17]

The entropy of the process in which the  individual ions first leave the crystal lattice is positive while the entropy of the process whereby the each ion becomes surrounded by a cluster of polar water molecules is negative.

<h3>What is entropy?</h3>

The term entropy has to do with the degree of disorder in a system. The higher the entropy of the system, the more the disorderliness of the system.

Now, the entropy of the process in which the  individual ions first leave the crystal lattice is positive while the entropy of the process whereby the each ion becomes surrounded by a cluster of polar water molecules is negative.

Learn more about entropy: brainly.com/question/13146879

3 0
2 years ago
One of the emission spectral lines for Be3+ has a wavelength of 253.4 nm for an electronic transition that begins in the state w
4vir4ik [10]

Answer:

4

Explanation:

Relationship between wavenumber and Rydberg constant (R) is as follows:

wave\ number=R\times Z^2\frac{1}{n_1^2} -\frac{1}{n_1^2}

Here, Z is atomic number.

R=109677 cm^-1

Wavenumber is related with wavelength as follows:

wavenumber = 1/wavelength

wavelength = 253.4 nm

wavenumber=\frac{1}{253.4\times 10^{-9}} \\=39463.3\ cm^{-1}

Z fro Be = 4

39463.3=109677\times 4^2(\frac{1}{n_1^2} -\frac{1}{5^2})\\39463.3=109677\times 16(\frac{1}{n_1^2} -\frac{1}{5^2})\\n_1=4

Therefore, the principal quantum number corresponding to the given emission is 4.

6 0
4 years ago
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