Answer:
Approximately 
.
Explanation:
Cathode is where reduction takes place and anode is where oxidation takes place. The potential of a electrochemical reaction (
) is equal to
.
There are two half-reactions in this question. 
and 
. Either could be the cathode (while the other acts as the anode.) However, for the reaction to be spontaneous, the value of should be positive.
In this case, is positive only if is the reaction takes place at the cathode. The net reaction would be
.
Its cell potential would be equal to 
.
The maximum amount of electrical energy possible (under standard conditions) is equal to the free energy of this reaction:
,
where
is the number moles of electrons transferred for each mole of the reaction. In this case the value of is 
as in the half-reactions.
is Faraday's Constant (approximately 
.)
.
Answer:
all I know is C
are there more questions? anyone?
-KARL IS STOOPID
Explanation:
Answer:
V is approximately = 23m/s
Explanation:
Kinetic energy = ½ mv²
Where m= mass = 0.450kg
V= velocity =?
K. E = 119J
Therefore
K. E = ½ mv²
Input values given
119= ½ × 0.450 × v²
Multiply both sides by 2
119 ×2 = 2 × 1/2 × 0.450 × v²
238= 0.450v²
Divide both sides by 0.450
238/0.450 = 0.450v²/0.450
v² = 528.89
Square root both sides
Sq rt v² = sq rt 528.89
V = 22.998m/s
V is approximately = 23m/s
I hope this was helpful, please rate as brainliest
c) 101kPa
Hope I helped! ( Smiles )
Answer:
I don't think the information is complete
