After alpha decay (234,90) remain from it
Answer: (2) releases 2260 J/g of heat energy
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Latent heat of condensation is energy released when 1 mole of vapor condenses to form liquid droplets.
The temperature does not change during this process, so heat released goes into changing the state of the substance, thus it is called latent which means hidden. The energy released in this process is same in magnitude as latent heat of vaporization. The heat of condensation of water vapour is about 2,260 J/g.
Elements are grouped into periods and groups . Elements with same number of energy shells are in the same period and elements with the same number of electrons in the outermost energy shells are in the same group.
Reactivity depends on the number of valence electrons. Number of valence electrons the element has will determine if the element needs to gain electrons or give out electrons.
Therefore elements with same number of valence electrons will have similar chemical properties .
When you look at elements in the same group(column) they have similar chemical properties
Answer:
Explanation:
To interpret this pedigree, let’s start with information that we already know:
Brown is recessive, which means brown individuals must have the phenotype BB. In this pedigree, brown individuals are filled in.
Black is dominant, which means black individuals must have at least one B allele. Their phenotype could be either BB or BB. In this pedigree, black individuals are not filled in.
Figure 5 shows the same pedigree, but with information about the individual’s phenotype filled in.
The shaded individual, who is a brown female puppy, must have the phenotype BB. If she had any B alleles, she would be black because the black allele is dominant over the brown allele.
In order for the brown puppy to have the phenotype BB, she must have gotten two “b” alleles: one from each of her parents. We know that her parents are both black (because they are unshaped), which means they must have a least one “B” allele. This means that both parents must be heterogeneous: BB.
The three black puppies must have at least one “B” allele in order for them to be black in color. However, we can’t tell whether they are homologous dominant (BB) or heterogeneous (BB) since both of those phenotype would result in black color. One way to represent this on a pedigree is B-, meaning that the second allele could be either B or b.
The answer should be D
Hope this helps
~ Jordan ~