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RoseWind [281]
3 years ago
6

Solve by factoring 2x^2=19x+33

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
5 0

<span>2x^2 - 19x - 33 = 0 </span>

<span>The factors of 2 are 1 x 2. </span>
<span>The factors of 33 are 1 x 33 and 3 x 11. </span>

<span>Using Guess and Test and FOIL, find a combination that gives you a middle term of -19x: </span>

<span>(2x + 3)(x - 11) = 0. </span>

<span>Using the principal of zero product, solve each equation for x: </span>

<span>2x + 3 =0 and x - 11 =0. </span>

<span>The two solutions are x = -3/2 and x = 11.

</span>
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Calculate f(x) for the given domain values.
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Answer:

See explanation

Step-by-step explanation:

1. The given function is

f(x) =  - 3x

The domain values are: x=0, 2, -1, 4, -2

When x=0

f(0) =  - 3 \times 0 = 0

When x=2,

f(x) =  - 3 \times 2 =  - 6

When x=-1

f(x) =  - 3 \times  - 1  = 3

When x=4

f(4) =  - 3 \times 4 =  - 12

When x=-2

f( - 2) =  - 3 \times  - 2 = 6

2. The given function is

f(x) =  \frac{1}{3} x

When x=3,

f(3) =  \frac{1}{3}  \times 3 = 1

Similarly,

f( - 3) =  \frac{1}{3}  \times  - 3 =  - 1

f(300) =  \frac{1}{3}  \times 300 = 100

f( - 180) =  \frac{1}{3}  \times  - 180 =  - 60

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3 years ago
HELP!
kondor19780726 [428]
144/200=0.72 or 72%

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d1i1m1o1n [39]

Answer:

The answer is 8.

Step-by-step explanation:

The scale factor between the figures is 2/3, this means that the ratio of the smaller figure to the larger figure is 2/3:

\frac{smaller\:figure}{larger\:figure}=\frac{2}{3}.

So when a side of the the larger figure is 12 then:

\frac{smaller\:figure\: side}{12}=\frac{2}{3}

Therefore

smaller\:figure\:side=\frac{2}{3}*12=8.

Thus the length of the corresponding smaller side is 8.

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3 years ago
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g100num [7]

Answer:

Heun's method is also known by its other name called Modified Euler methods. This method is used in computational or mathematical science.

Step-by-step explanation:

Euler method is the method that is also pronounced in two similar stages such as Runge- Kutta methods. This method has been named after Dr. Heun.

This method is used for the solution of ordinary differential equations with its given values. There is some method to calculate this method. The improved Runge Kutta methods are also called the Butcher tableau method, the other methods are also called the Ralston methods.

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5) True thath the equation of the line perpendicular to the y-axis that passes through the point (–5, 1) is y = 1
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