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mr Goodwill [35]
3 years ago
5

What is a gene?

Physics
1 answer:
grandymaker [24]3 years ago
3 0

Answer:B. A segment of a DNA molecule

Explanation:

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What is the diamnsanion of force
tensa zangetsu [6.8K]

Answer:

spelling ?

Explanation:

6 0
3 years ago
A student has two 150kΩ resistors and two 200ߤF capacitors from which to create an RC circuit. Determine each of the possible ci
FrozenT [24]

Answer:

The time constants 30 seconds and the can form an RC Charging circuit.

Explanation:

Time constant, τ, is measured in terms of τ = R x C, in seconds, where R is the value of the resistor in ohms and C is the value of the capacitor in Farads

If R = 150 kΩ = 150000Ω

and C = 200 μF = 0.0002 F

τ = 150,000 × 0.0002

<u>= 30 seconds.</u>

A capacitor, (C)  connected in series with a resistor, (R) forms a RC Charging Circuit connected across a DC battery supply (Vs) via a mechanical switch, with transient time (time required to charge capacitor) = 5τ

3 0
3 years ago
A string has a mass of 0.8Kg. The length of the string is 2m. The tension in the string is 5N. The string is stretched and fixed
viktelen [127]

Answer:

1.25Hz

Explanation:

For waves on a string, the second harmonic is obtained from;

2fo = 1/l √T/M

Where;

l = length of the string

M= mass in kilograms

T = tension in the string

2fo = 1/2√5/0.8

2f0 = 1.25Hz

3 0
3 years ago
A system in which only one particle can move has the potential energy shown in (figure 1). Suppose u1 = 60 j. What is the y-comp
marta [7]

The y-component of the force on the particle at the given position is 120 N.

<h3>Electric force on the particle</h3>

The electric force on the particle is determined by applying Coulomb's law and work-energy theorem as shown below;

Fd = W

Where;

  • F is the applied force
  • d is the distance
  • W is potential

F = W/d

F = 60/0.5

F = 120 N

Thus, the y-component of the force on the particle at the given position is 120 N.

Learn more about electric force here: brainly.com/question/20880591

3 0
2 years ago
A bucket that has a mass of 20 kg when filled with sand needs to be lifted to the top of a 15 meter tall building. You have a ro
prohojiy [21]

Answer:

work done lifting the bucket (sand and rope) to the top of the building,

W=67.46 Nm

Explanation:

in this question we have given

mass of bucket=20kg

mass of rope=.2\frac{kg}{m}

height of building= 15 meter

We have to find the work done lifting the bucket (sand and rope) to the building =work done in lifting the rope + work done in lifting the sand

work done in lifting the rope is given as,W_{1}=Force \times displacement

=\int\limits^{15}_0 {.2x} \, dx ..............(1)

=.1\times 15^2

=22.5 Nm

work done in lifting the sand is given as,W_{2}=Force \times displacement

W_{2}=\int\limits^{15}_0 F \, dx.................(2)

Here,

F=mx+c

here,

c=20-18

c=2

m=\frac{20-18}{15-0}

m=.133

Therefore,

F=.133x+2

Put value of F in equation 2

W_{2}=\int\limits^{15}_0 (.133x+2) \, dx

W_{2}=.133 \times 112.5+2\times15\\W_{2}=14.96+30\\W_{2}=44.96 Nm

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,W=W_{1}+W_{2}

W=22.5 Nm+44.96 Nm

W=67.46 Nm

4 0
4 years ago
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