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3 years ago

Why does the comet have tails

Physics

2 answers:

docker41 [41]3 years ago

8 0

Answer:

Comets leave long beautiful tails when they come close to the sun. ... But when it approaches the sun, the heat evaporates the comet's gases, causing it to emit dust and microparticles (electrons and ions). These materials form a tail whose flow is affected by the sun's radiation pressure.

Explanation: I just searched it up on the internet lol.

SVEN [57.7K]3 years ago

8 0

Answer:

when it approaches the sun, the heat evaporates the comet's gases, causing it to emit dust and micro particles

Explanation:

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Does most psychologists believe that ESP exist

vodomira [7]

Answer:

Explanation:

most psychologists are skeptical of ESP and believe it's not real. There actually more skeptical of ESP than other scientists.

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3 years ago

The voltage and the current in the primary coil of a nonideal transformer are 120 volts and 2.0 amperes. The voltage and the cur

Arlecino [84]

Explanation:

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3 years ago

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sammy [17]

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3 years ago

A research van de graaff generator has a 2.30 m diameter metal sphere with a charge of 1.10 mc on it. (a) what is the electric p

juin [17]

The potential on the surface of the charged sphere is 3.9 × 10⁷ volts.

Given:

The diameter of the sphere is 2.30 m and the charge of 1.10 mc.

The potential on the surface of a charged sphere is given by,

$V=k\frac{Q}{R}$

Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.

V = 8.99×10⁹×5×10⁻³/(2.30÷2)

V = 3.9 × 10⁷ volts

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2 years ago

A three-point bending test was performed on an aluminum oxide specimen having a circular cross section of radius 6.7 mm; the spe

mart [117]

Answer:

at load 13114.85 N beam fail

Explanation:

given data

radius r = 6.7 mm

load = 2710 N

distance = 41 mm

length = 19 mm

to find out

At what load we expect this specimen to fracture

solution

we will first flexural strength that is

flexural strength = load × distance / πr³

flexural strength = 2710 × 41 × $10^{-3}$ / π(6.7 × $10^{-3}$ )³

flexural strength = 117.592 MPa

we know that for cross section specimen

flexural strength = 3load × distance / 2bd²

put here these value

117.592 × $10^{6}$ N/m² = 3 load × 41 × $10^{-3}$ / ( 2 × (19× $10^{-3}$ )³)

load = 117.592 × $10^{6}$ × ( 2 × (19× $10^{-3}$ )³) / ( 3 × 41 × $10^{-3}$ )

load = 13114.85 N

so at load 13114.85 N beam fail

4 0

3 years ago