Answer:
49.95 g of HCl
Explanation:
Let's formulate the chemical equation involved in the process:
Ca(OH)2 + 2 HCl → CaCl2 + 2 H2O
This means that we need 1 mole of Calcium hydroxide to neutralize 2 moles of hydrochloric acid. From this, we calculate the quantity of HCl moles that would be neutralized by 0.685 moles of Ca(OH)2
1 mole Ca(OH)2 ---- 2 moles HCl
0.685 moles Ca(OH)2 ---- x = 1.37 moles HCl
Now that we know the quantity of HCl moles that would react, let's calculate the quantity of grams this moles represent:
1 mole of HCl ---- 36.46094 g
1.37 moles ------ x = 49.95 g of HCl
The final volume reading on the graduated cylinder is 12.52ml
Density = mass / volume
Volume = mass / density
Volume of zinc = 2.83/7.14
Volume of zinc = 0.3963
Initial volume = 12.13 ml
Total volume = initial volume+ volume of zinc
Total volume = 12.13 + 0.3963
Total volume = 12.5263 = 12.52 ml
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Answer: 8.38 seconds
Explanation:
Integrated rate law for second order kinetics is given by:
= initial concentartion = 0.860 M
a= concentration left after time t = 0.230 M
k = rate constant =
Thus it will take 8.38 seconds for the concentration of A to decrease from 0.860 M to 0.230 M .
Answer:
B
Explanation:
follow the chart starting at the y axis go away from it at the level of 1 till you hit 100
Because of the surface tention.