What gas? Gas is an invisible form so I don't see how it would have a "defined structure".
Answer:

Explanation:
Given that:

R = (0.1) m
To find the electric field for r < R by using Gauss Law

For r < R



where;




Answer: the answer would be four thousand
Explanation: hope this helps
<span>Taking into account the information above, we know the average mass of the bucket of water may be m=20-5/2=17.5kg. As the bucket of water is pulled at a "constant velocity" the work required to raise the bucket to the platform transformed into the potential energy of the bucket of water. That is why it should be W=mgh=17.5*9.8*40=6860J</span>
Desireurban has given a good discussion in the first answer,
but be careful with it:
-- Yes, skimming instead of reading carefully can be non-productive.
-- Using credible sources is MORE productive, and using less reliable sources
can be LESS productive.
Another nonproductive learning behavior ... one that I worry about a lot ...
is slapping the question up on Brainly and waiting for someone to give
you the answer, instead of taking some time to think about it.