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Nat2105 [25]
3 years ago
12

The element vanadium is a solid at room temperature, and its density is 6110 kilograms per meter cubed. Its melting point is 191

0 degrees Celsius. Which correctly evaluates the statement?
Chemistry
2 answers:
m_a_m_a [10]3 years ago
7 0

Answer:

<h3>reliable because testable facts are presented</h3>

Phantasy [73]3 years ago
5 0
<span>Consider the following statement:

"The element vanadium is a solid at room temperature, and its density is 6110 kilograms per meter cubed. Its melting point is 1910 degrees Celsius."

Which correctly evaluates the statement?</span><span>
Answer:
reliable because testable facts are presented</span>
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salantis [7]

Answer:

engey

Explanation:

7 0
3 years ago
A balloon containing 0.0400 mol of a gas with a volume of 500 mL was expanded to 1.00 L. Answer the questions and round answers
grandymaker [24]

the number of moles 0.08

8 0
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What volume of stock solution and water must you add to prepare 36.25ml of a 1.25M solution
Serjik [45]

Given :

Number of moles , n = 36.25 mol .

Molarity , M = 1.25 M .

To Find :

The volume of water required .

Solution :

Moarity is given by :

M=\dfrac{n}{V}

So , V=\dfrac{n}{M}

Here , n is number of moles and M is molarity .

Putting all values in above equation , we get :

V=\dfrac{36.25}{1.25}\\\\V=29\ L

Therefore , volume of water required is 29 L .

5 0
3 years ago
Stable nuclei with low atomic numbers, up to 20, have a neutron to proton ratio of approximately ________.
Pie
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6 0
4 years ago
Bob measured out 1.60 grams of sodium. He calculates that 1.60 g of
saul85 [17]

Answer:

84.8%

Explanation:

Step 1: Given data

Bob measured out 1.60 g of Na. He forms NaCl according to the following equation.

Na + 1/2 Cl₂ ⇒ NaCl

According to this equation, he calculates that 1.60 g of sodium should produce 4.07 g of NaCl, which is the theoretical yield. However, he carries out the experiment and only makes 3.45 g of NaCl, which is the real yield.

Step 2: Calculate the percent yield.

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 3.45 g / 4.07 g × 100% = 84.8%

6 0
3 years ago
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