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natta225 [31]
4 years ago
15

An object is made up of three masses connected by massless rods of fixed length. Mass A is located at (30.0 cm, 0 cm) and has a

mass of 250 grams, mass B is located at (0 cm, 40.0 cm) and has a mass of 350 grams, mass C is located at (-20.0 cm, 0 cm) and has a mass of 450 grams. What is the moment of inertia of this object about an axis perpendicular to the x-yplane and passing through the origin
Physics
1 answer:
puteri [66]4 years ago
8 0

Answer:

0.0605 Kg m^2

Explanation:

In this case where we have find he moment of inertia of this object about an axis perpendicular to the x-y plane and passing through the origin,  we can just add three moment of inertia's .

MOI= 0.25×0.3^2 + 0.35×0.4^2- 0.45×0.2^2

= 0.0605 Kg m^2

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Answer with Explanation:

We are given that

F=-8\hat{i}+6\hat{j}

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a.We have to find the torque on the particle about the origin.

We know that

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By using the formula

\tau=50\hat{k}

b.\mid \tau\mid =\mid F\mid \mid r\mid sin\theta

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Substitute the values then we get

50=10\times 5 sin\theta

sin\theta=\frac{50}{50}=1

sin\theta=sin90^{\circ}

Because sin90^{\circ}=1

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