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miskamm [114]
3 years ago
13

6. How many sections are there to an SDS for a given chemical? *

Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0
The answer would be 16
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Sirius, the brightest star, is 8.8 light-years from Earth. That means
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C) we can see Sirius as it looked 8.8 light years ago.
6 0
3 years ago
Name the following compounds:
HACTEHA [7]

CaF2 = Calcium fluoride (leave it as is, it in emoerical form already)

Na20 = Sodium oxide (leave it as is, it in emoerical form already)

BaS = Barium Sulfide (leave it as is, it in emoerical form already)

CuSO4 = Copper(II) sulfate = CuSO4 5H2O

Fe2O3 = Iron(III) oxide (leave it as is, it in emoerical form already)

HgCl2 = Mercury(II) chloride (leave it as is, it in emoerical form already)

KC2H3O2 = Potassium Acetate (leave it as is, it in emoerical form already)

Al(OH)3 = Aluminium hydroxide (leave it as is, it in emoerical form already)

Fe(NO3)3 = Iron(III) nitrate (leave it as is, it in emoerical form already)

N2O5 = Dinitrogen pentoxide = N2O5 (it's subscrip is already simplified)

PO5 = Phosphorus pentoxide = P2 O5 (there was just no 2 after the P so that's all that was needed there)

I'm am so sorry if this didn't help too much, I hope I did help, I in some way, have a wonderful day.

3 0
3 years ago
Calculate the amount of heat required to heat a 3.3 kg gold bar from 26 ∘C to 69 ∘C. Specific heat capacity of gold is 0.128 J/g
kaheart [24]
To answer the question above, we make use of the equation,
                          heat = (specific heat ) x mass x (change in temperature)
Substituting the known values,
                       heat = (0.128 J/g°C) x (3.3 kg)(1000g / 1kg) x (69°C - 26°C)
                               = 18163.2 J
Therefore, the amount of heat required is approximately 18163.2 J. 
6 0
3 years ago
Read 2 more answers
Increasing the volume of a given amount of gas at constant temperature causes the pressure to decrease because
mestny [16]
Because the molecules are more spread apart.

(gas spread)
5 0
3 years ago
Read 2 more answers
What is the density of mass=108g volume=5.64cm3
nordsb [41]

Answer:

19.15kg/m³

Explanation:

density=mass/volume

d=m/v

d=108/5.64

19.15kg/m³

6 0
3 years ago
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