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rewona [7]
3 years ago
8

How many neutrons are in 7.00 g of 13c?

Chemistry
1 answer:
Minchanka [31]3 years ago
5 0
You multiply the number of atoms by 12 to get how many electrons (since each atom has 12 electrons in it)
you multiply the number of atoms by 13 to get how many neutrons
(since each atom of this isotope has 13 neutrons in it)
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How many grams are in 0.535 moles of sodium bromide? (Please add work)
anastassius [24]

Answer:

0.535 = 55.04816695 grams

Explanation:

0.009718761398284852 moles = 1 gram

3 0
2 years ago
Which one could be considered pure substances? And why
Sergeu [11.5K]
I think it would be water but im not sure! Hope that helps!!
6 0
3 years ago
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A graduated cylinder contains 20.5 mL of water. What is the new water level after 35.2 g of silver metal with a density of 10.5
iragen [17]
 <span>V = 24.0 mL + (35.2 g)(mL/10.5g) = I think i'm not all that sure but I think its this.</span>
3 0
2 years ago
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The mass of an electron is 9.11× 10–31 kg. What is the uncertainty in the position of an electron moving at 2.00 × 106 m/s with
Kruka [31]
Just use the Heisenberg Uncertainty principle: 

<span>ΔpΔx = h/2*pi </span>

<span>Δp = the uncertainty in momentum </span>
<span>Δx = the uncertainty in position </span>
<span>h = 6.626e-34 J s (plank's constant) </span>

<span>Hint: </span>

<span>to calculate Δp use the fact that the uncertainty in the momentum is 1% (0.01) so that </span>

<span>Δp = mv*(0.01) </span>

<span>m = mass of electron </span>
<span>v = velocity of electron </span>

<span>Solve for Δx </span>

<span>Δx = h/(2*pi*Δp) </span>

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6 0
3 years ago
(06.04 HC)
Ksju [112]

The mass of sodium chloride at the two parts are mathematically given as

  • m=10,688.18g
  • mass of Nacl(m)=39.15g

<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Where the chemical equation is

F2 + 2NaCl → Cl2 + 2NaF

Therefore

1.50x15=m/M *(1.50*0.0821)

1-50 x 15=m/58.5 *(1.50*0.0821)

m=10,688.18g

Part 2

PV=m'/MRT

1*15=m'/58.5*0.0821*273

m'=39.15g

mass of Nacl(m)=m'=39.15g

Read more about Chemical Reaction

brainly.com/question/11231920

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7 0
1 year ago
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