Question

If 12^x2+^5x-4=12^2x+6, what could be the value of x?

Answer 1

Answer:

$x=-5, x=2$

Step-by-step explanation:

we have

$12^{(x^{2}+5x-4)}=12^{(2x+6)}$

Since the both have the same base $12$

${(x^{2}+5x-4)}={(2x+6)}$

$x^{2}+5x-4-2x-6=0$

$x^{2}+3x-10=0$

Using a graphing tool ------> resolve the quadratic equation

see the attached figure

The solutions are

$x=-5, x=2$

Answer 2

Since the both have the same base 12 you can write like thus
X^2+5x-4=2x+6
X^2+5x-4-2x-6=0
X^2+3x-10=0
(X-2)(X+5)
X-2=0. X+5=0
X=2. And X=-5