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3 years ago

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Four grams of magnesium react with an excess of dilute hydrochloric acid. Calculate the volume in liters of hydrogen gas collect

ed over water at 300 K, if the vapor pressure of water at that temperature is 26.7 mm and the barometric pressure is 730 mm

1 answer:

Helga [31]3 years ago

5 0

Sorry I am confuse 3

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Which idea did linnaeus contribute to the theory of evolution

MissTica

Answer:

Binomial Naming System

Explanation:

He was the first to use the system, he used it frequently enough for the system to be accepted and used more often by scientists. He believed that species were unable to be changed.

6 0

3 years ago

What is the reducing agent in the reaction below?

trapecia [35]

Al is the reducing agent.That is answer B is the above answer
Al acts as a strong reducing agent. It reduces crO3 to form cr while Al is oxidized to Al2O3. Al is capable to reduce cr since Al is higher in reactivity series than cr.

8 0

3 years ago

Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. CO + O2 → CO2

liberstina [14]

Answer:

2co + o2 > 2co2

Explanation:

so that is tye answer

3 0

3 years ago

Read 2 more answers

how many moles of iron will be produced from 6.20 moles of carbon monoxide reacting with excess iron (III) oxide (FeO3) to produ

Gelneren [198K]

0.20 moles of iron will be formed in the reaction.

Explanation:

The balanced chemical equation for the reaction between iron (iii) oxide and carbon monoxide to form Fe is to be known first.

the balanced reaction is :

Fe2O3 + 3CO⇒ 2 Fe + 3 CO2

so from the data given the number of moles of carbon monoxide can be known:

3 moles of CO reacted with Fe2O3 to form 2 moles of iron in the reaction.

Number of moles of CO is 6.20 moles

11.6 gm of iron is formed

so the number of moles of iron formed is calculated as

n = mass of iron ÷ atomic weight of iron

= 11.6 ÷ 55.84

= 0.20 moles of iron will be formed when 11.6 gram of iron is produced.

5 0

3 years ago

4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration

anzhelika [568]

Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.

<h3>Definition of percent composition </h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

<h3>Percentage Composition in this case</h3>

In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.

Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:

$percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100$

<u><em>percentage composition of potassium iodide= 0.017%</em></u>

Finally, the percent composition of potassium iodide in this sample is 0.017%.

Learn more about percent composition:

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3 0

2 years ago