Answer:
17 g Ba(NO₂)₂
General Formulas and Concepts:
<u>Chemistry</u>
- Stoichiometry
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
4.5 × 10²² molecules Ba(NO₂)₂
<u>Step 2: Define conversion</u>
Molar Mass of Ba - 137.33 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol
<u>Step 3: Dimensional Analysis</u>
<u />
= 17.1384 g Ba(NO₂)₂
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂
Answer: The change in volume will be 9.30 L
Explanation:
To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:

where,
are initial pressure and volume.
are final pressure and volume.
We are given:

Putting values in above equation, we get:

The change in volume will be (44.3-35.0)L = 9.30 L
The cell notation is
║
and the cell potential is 0.464
The reaction occurred while losing of hydron is known as oxidation reaction
We can also tell that the reaction occurred while gaining of oxygen atom is known as oxidation reaction.
The reaction occurred while gaining of hydrogen is known as reduction reaction or we can say that the reaction occurred while losing oxygen atom is known as reduction reaction
An electrochemical cell's cell potential is defined as the difference in potential between two half cells. The electrons' capacity to go from one half cell to the other is what causes the potential difference. As a result of the chemical reaction being a redox reaction, electrons can travel across electrodes.
Calculating the Cell potential
E°cell = E°(reduction) - E°(oxidation)
= 0.34 - (-0.0124)
= 0.464
Hence the cell potential is 0.464
Learn more about Cell potential here
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