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serg [7]
2 years ago
11

Jada, Diego, and Elena each use the same spinner that has four (not necessarily equal sized) sections marked A, B, C, and D.

Mathematics
1 answer:
natta225 [31]2 years ago
8 0

Answer:

diego

Step-by-step explanation:

diego is right cause the spinner has four sides and he spun 5 times

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Write an equation of the circle with center (5, -7) and radius 9.
vagabundo [1.1K]

Answer:

(x - 5)² + (y + 7)² = 81

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (5, - 7) and r = 9, thus

(x - 5)² + (y - (- 7))² = 9², that is

(x - 5)² + (y + 7)² = 81 ← equation of circle

6 0
2 years ago
Which is the closest to the quotient 4367/0.004​
VladimirAG [237]

Answer:

1091750

Step-by-step explanation:

if your dividing

8 0
3 years ago
Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past
blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0
3 years ago
What is the answer for 7-4x=2+x+6-5x
levacccp [35]

Answer:

no solution

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Joni has a circular garden with a diameter of 14 1/2 feet if she uses 2 teaspoons of fertilizer for every 25 square feet of gard
alina1380 [7]

Answer:

13.20 teaspoon of fertiliser needed for entire garden.

Step-by-step explanation:

Diameter of the garden = 14.50 ft

Radius of the garden = 7.25 ft

Area

[tex]A=\pi r^2[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]\pi=3.14[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]A=3.14 \times 7.25 \times 7.25[/text]

Hence

[tex]A=165.046[/text]

Area is 165.046 Sq Ft

For 25 sq ft of fields the fertiliser needed = 2 tea spoon

For 1 sq ft of fields the fertiliser needed =

[tex]\frac{2}{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed =

[tex]\frac{2 \times 165.046 }{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed = 13.20 tea spoon

6 0
2 years ago
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